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o-na [289]
3 years ago
8

Find surface area of the right angled triangular prism.

Mathematics
2 answers:
valentinak56 [21]3 years ago
7 0

Answer:

SA=504\text{ cm}^2

Step-by-step explanation:

We have been given an a right angled triangular prism. We are asked to find the surface area of our given prism.

We will use surface area of right prism formula to solve our given problem.

SA=2B+Ph, where,

SA = Surface area,

B = Area of right triangular base,

P = Perimeter of right triangular base,

h = Height of prism.

Let us find area of of triangular base.

B=\frac{1}{2}\times 9\times 12

B=9\times 6

B=54

The perimeter of triangular base would be 9+12+15=36.

Upon substituting our given values, we will get:

SA=2(54)+36(11)

SA=108+396

SA=504

Therefore, the surface area of our given prism is 504 square cm.

jeka57 [31]3 years ago
6 0
A triangular prism<span> has 5 faces, 3 being rectangular and 2 being </span>triangular<span>. The </span>area<span> of the rectangular faces can be found by multiply the base and height lengths together. The </span>area<span> of the </span>triangular<span> faces can be found by multiplying the base and height and dividing by 2.</span>
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Answer:

= 1/2

Step-by-step explanation:

From the question: 1 bag contains

4 cotton candy lollipops

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= 4/14 + 3/14

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Dafna1 [17]

Answer:

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Step-by-step explanation:

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7 0
3 years ago
What is the circumference of a circle with area 50cm2. Give your answer to three significant figures.
Mnenie [13.5K]

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Step-by-step explanation:

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Mark me brainly plz

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3 years ago
Which Two Numbers Add Up To Negative 26 And Multiply To 11?
Fynjy0 [20]
Xy=11
x+y=-26


x+y=-26
minus x both sides
y=-26-x

sub for y
x(-26-x)=11
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x^2+26x+11=0

ax^2+bx+c=0
x=\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}


a=1
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x=\frac{-26+/-\sqrt{26^{2}-4(1)(11)} }{2(1)}
x=\frac{-26+/-\sqrt{676-44} }{2}
x=\frac{-26+/-\sqrt{632} }{2}
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aprox

x=-0.420195 or -25.5698

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5 0
3 years ago
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