Answer:
The garden can not have area of 700ft^2
Step-by-step explanation:
We are given equation for area as

where
w is the width (in feet) of the garden
now, we are given area =700 ft^2
so, we can set area =700
and then we can solve for w



now, we can use quadratic formula


we can compare and find a,b, and c
a=-1 , b=50 , c=-700
now, we can plug values


We can see that values of w is not real
so, w does not exists when area =700
so, The garden can not have area of 700ft^2
<h2>
Answer: </h2>
formula = Multiply mass with 1000.
weight of a pack of oranges = 7.4 kg
weight of the pack of oranges in grams = 7.4 x 1000 = 7,400g
<h2><u>
Weight of the pack of oranges in grams is 7,400g</u></h2>
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Answer:
35/4, or 8 3/4 as a mixed number
Step-by-step explanation:
First, change 58 1/3 into an improper fraction by multiplying the whole number and denominator, then adding the numerator. 58 x 3 equals 174, + 1 equals 175. So, 58 1/3 as an improper fraction is 175/3. Next, change 6 2/3 into an improper fraction. 6 times 3 equals 18, plus 2 equals 20. So, it's 20/3. So, here are your two fractions:
175/3 & 20/3
To divide fractions, I like to use a method called Keep Change Flip. Basically, you keep the first fractions the same, then change the sign. The division sign changes into a multiplication symbol. Now, your equation should look like this: 175/3 x 20/3. Next, flip the fraction from 20/3 into 3/20. This is what your equation should look like now: 175/3 x 3/20. Now you can multiply the fractions together. Before you do so, you can cross reduce to make it easier. What is a number that both 3 and 3 can be divided by? The correct answer is 3. 3/3= 1, so the equation is now 175/1 x 1/20. However, you can continue to cross reduce. You can also divide 175 and 20 by 5, so the equation changes into this: 35/1 x 1/20. Multiply numerator by numerator, denominator by denominator. So, the answer is 35/4, or 8 3/4 as a mixed number. Hope this helped!
With

we have

The vector field evaluated over this parameterization is

so the line integral is

