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Mademuasel [1]
3 years ago
8

Evaluate (-5)^2 10 -10 25 -25

Mathematics
2 answers:
Lady bird [3.3K]3 years ago
5 0
Answer: C) 25

Because if you multiply -5 × -5 = 25
The negative sign goes away
elena55 [62]3 years ago
5 0

Answer:

Hey!

Your answer is 25!

Step-by-step explanation:

When we see (-5)^2 it means we multiply -5 by -5

(-5 x -5)

When you multiply two negatives, it becomes a positive!!

So we now see this as 5 x 5 which gives you 25!!

HOPE THIS HELPS!!

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Find the exact value of cos(sin^-1(-5/13))
son4ous [18]

bearing in mind that the hypotenuse is never negative, since it's just a distance unit, so if an angle has a sine ratio of -(5/13) the negative must be the numerator, namely -5/13.

\bf cos\left[ sin^{-1}\left( -\cfrac{5}{13} \right) \right] \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{then we can say that}~\hfill }{sin^{-1}\left( -\cfrac{5}{13} \right)\implies \theta }\qquad \qquad \stackrel{\textit{therefore then}~\hfill }{sin(\theta )=\cfrac{\stackrel{opposite}{-5}}{\stackrel{hypotenuse}{13}}}\impliedby \textit{let's find the \underline{adjacent}}

\bf \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{13^2-(-5)^2}=a\implies \pm\sqrt{144}=a\implies \pm 12=a \\\\[-0.35em] ~\dotfill\\\\ cos\left[ sin^{-1}\left( -\cfrac{5}{13} \right) \right]\implies cos(\theta )=\cfrac{\stackrel{adjacent}{\pm 12}}{13}

le's bear in mind that the sine is negative on both the III and IV Quadrants, so both angles are feasible for this sine and therefore, for the III Quadrant we'd have a negative cosine, and for the IV Quadrant we'd have a positive cosine.

8 0
3 years ago
What are the points for f(x)=3^(x-1)-2
Savatey [412]

Answer:  (0, -1 \frac{2}{3}), (1, -1), (2, 1)

<u>Step-by-step explanation:</u>

Set the exponent equal to zero - <em>that is your anchor point</em>.

Then choose an x-value less than and greater than the anchor point.

\left\begin{array}{c|c|l}&\underline{\quad x\quad }&\underline{\qquad \qquad f(x)\qquad \qquad \qquad \quad }\\\text{less than anchor}&0&3^{0-1}-2=3^{-1}-2=\frac{1}{3}-2 = -1\frac{2}{3}}\\\\anchor\ point&1&3^{1-1}-2=3^{0}-2=1-2 = -1}\\\\\text{greater than anchor}&2&3^{2-1}-2=3^{1}-2=3-2 = 1}\end{array}\right

4 0
3 years ago
Shawna cuts out a square piece of card stock paper for a project. Her partner Tanisha wants to check to see if the cutout is act
My name is Ann [436]

Answer:

Yes

Step-by-step explanation:

Reason is that a square has all the aspects of a parallelogram a rectangle and a rhombus. It gets its congruent diagonals from the rectangle which is congruent

6 0
2 years ago
What is the length of AB?
Xelga [282]

Answer:

<em>AB = 7.35 cm</em>

Step-by-step explanation:

From the attachment,

In ΔDEF,

DF = GH-(GD+FH) = 6 - (2+3) = 1 cm

DE = 2+3 = 5 cm (sum of two radius)

Applying Pythagoras theorem,

EF=\sqrt{DE^2-DF^2}=\sqrt{5^2-1^2}=\sqrt{24}=2\sqrt6

In ΔCDI,

DI = GH-(GD+IH) = 6 - (2+1.5) = 2.5 cm

CD = 2+1.5 = 3.5 cm (sum of two radius)

Applying Pythagoras theorem,

CI=\sqrt{CD^2-DI^2}=\sqrt{3.5^2-2.5^2}=\sqrt6

AB = EF + CI = 2\sqrt6+\sqrt6=3\sqrt6=7.35\ cm

6 0
3 years ago
Read 2 more answers
The equation C(l) = l3 – l2 + l + 2.5 models the cost to mail a package as a function of its length. To the nearest quarter inch
____ [38]

Answer:

2.25

Step-by-step explanation:

Given the cost model:

C(l) = l3 – l2 + l + 2.5

l = Length fo package

The length of a package that cost $11.00

11 = l³ - l² + l + 2.5

From the table given :

Length of mail which cost $11 will just be slightly greater Than 2 as the cost of 2 length mail cost 8.50

Taking l as 2.20

2.2^3 - 2.2^2 + 2.2 + 2.50 = 10.508

Taking a slightly higher value :

Put l = 2.25

2.25^3 - 2.25^2 + 2.25 + 2.50 = 11.078

Ww can conclude that the length of mail would be 2.25

5 0
2 years ago
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