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iogann1982 [59]

2 years ago

14

the length of a rectangle is 9 inches more than the width. the perimeter is 54 inches. Find the length and width of the rectangl

e

1 answer:

Keith_Richards [23]2 years ago

7 0

W is width W+9 is length W+W+9=54 2w=45 45/2 W=22.5 Width is 22.5 length is 31.5

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- 16m’n-(-25m’n)+(-7m’n)Which of the following is equivalent to the expression above?

Westkost [7]

As a rule , - times - = + and - times + = -

$\begin{gathered} -16m^2n-(-25m^2n)+(-7m^2n\text{ ) } \\ =-16m^2n+25m^2n-7m^2n\text{ ( based on the rule above )} \\ =+9m^2n-7m^2n\text{ ( -16 + 25 = + 9 )} \\ =+2m^2n \end{gathered}$

Therefore the correct answer to the question is 2m squared n

5 0

7 months ago

Giovanna has two possible driving routes to her new workplace, and she is having a hard time figuring out which is faster. The f

Oliga [24]

Answer:

Experiment

Step-by-step explanation:

An observational study is a study where researchers simply collect data based on what is seen and heard and make inferences based on the data collected.

Whereas, Experimental studies are the ones where researchers introduce an intervention and study the effects.

Giovanna did not just collect data alone and make inferences based on the collected data, as is done during an observational study, but she studied the effects of the data that she collected by calculating the average driving duration for each route.

Hence we see that she conducted an Experimental study.

5 0

2 years ago

Divide. Reduce the answer to lowest terms. 6 ÷ 4/5

Butoxors [25]

Answer:

I think its 7.5 but I might be wrong

Step-by-step explanation:

7 0

2 years ago

Uninhibited growth can be modeled by exponential functions other than A(t) =Upper A 0 e Superscript kt. For example, if an i

laila [671]

The question is incomplete. Here is the complete question.

Uninhibited growth can be modeled by exponential functions other than $A(t)=A_{0}e^{kt}$ . for example, if an initial population P₀ requires n units of time to triple, then the function $P(t)=P_{0}(3)^{\frac{t}{n} }$ models the size of the population at time t. An insect population grows exponentially. Complete the parts a through d below.

a) If the population triples in 30 days, and 50 insects are present initially, write an exponential function of the form $P(t)=P_{0}(3)^{\frac{t}{n} }$ that models the population.

b) What will the population be in 47 days?

c) When wil the population reach 750?

d) Express the model from part (a) in the form $A(t)=A_{0}e^{kt}$ .

Answer: a) $P(t)=50(3)^{\frac{t}{30} }$

b) P(t) = 280 insects

c) t = 74 days

d) $A(t)=50e^{0.037t}$

Step-by-step explanation:

a) n is time necessary to triple the population of insects, i.e., n = 30 and P₀ = 50. So, Exponential equation for growth is

$P(t)=50(3)^{\frac{t}{30} }$

b) In t = 47 days:

$P(t)=50(3)^{\frac{t}{30} }$

$P(47)=50(3)^{\frac{47}{30} }$

$P(47)=50(3)^{1.567}$

P(47) = 280

In 47 days, population of insects will be 280

c) P(t) = 750

$750=50(3)^{\frac{t}{30} }$

$\frac{750}{50}=(3)^{\frac{t}{30} }$

$(3)^{\frac{t}{n} }=15$

Using the property <u>Power</u> <u>Rule</u> of logarithm:

$log(3)^{\frac{t}{30} }=log15$

$\frac{t}{30}log(3)=log15$

$t=\frac{log15}{log3} .30$

t = 74

To reach a population of 750 insects, it will take 74 days

d) To express the population growth into the described form, determine the constant k, using the following:

A(t) = 3A₀ and t = 30

$A(t)=A_{0}e^{kt}$

$3A_{0}=A_{0}e^{30k}$

$3=e^{30k}$

Use Power Rule again:

$ln3=ln(e^{30k})$

$ln3=30k$

$k=\frac{ln3}{30}$

k = 0.037

Equation for exponential growth will be:

$A(t)=50e^{0.037t}$

3 0

2 years ago

5. Amber buys bottles of lemonade and a bag of cookies at the store. She pays a total of $9.50. The bag of cookies cost $3.25. I

Anika [276]

Answer:

each bottle was 1.25

Step-by-step explanation:

subtract 3.25 from 9.50 and then divide that answer by 5 for the 5 bottles of lemonade

3 0

1 year ago

Read 2 more answers