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nadya68 [22]
3 years ago
15

A football team won 8 more games than they lost. They played 24 games in the season. How many games were won and how many were l

ost?
Mathematics
1 answer:
Vaselesa [24]3 years ago
5 0

The team lost n games.

The team won 8 more games than it lost, so it won n + 8.

The total number of games the team played was n + n + 8, or 2n + 8.

The team played a total of 24 games, so

2n + 8 = 24

We now solve for n.

2n + 8 = 24

2n = 16

n = 8 (lost games)

n + 8 = 8 + 8 = 16 (won games)

Answer: The team won 16 games and lost 8 games.

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Explain your answer !! <br> Have a nice day <br><br> Will give braisnlt
Aleks [24]

Answer:

The price of hot dog is $2.5 and that of a pretzel is $1.25.

Step-by-step explanation:

Let the cost of hotdogs be h and that of pretzels be p.

So,

4h+3p = 13.75 ...(1)

and

2h+5p = 11.25 ...(2)

Multiply equation (2) by 2.

4h+10p = 22.5 ...(3)

Subtract equation (1) from (3).

4h+10p-(4h+3p) = 22.5-13.75

4h+10p-4h-3p = 8.75

7p = 8.75

y = 1.25

Put the value of y in equation (1).

4h+3(1.25) = 13.75

4h+3.75 = 13.75

4h = 13.75-3.75

4h = 10

h = 2.5

So, the price of hot dog is $2.5 and that of a pretzel is $1.25.

3 0
2 years ago
If ZP and ZQ are complementary angles,
nikdorinn [45]
The answer for this question is A because x is equivalent to 4
8 0
2 years ago
A school principal plans to form teams from 126 third-graders, 180 fourth-graders, and 198 fifth-graders so that there is the sa
marissa [1.9K]

Answer:

There are 9 teams possible each having 14 third-graders, 20 Fourth-graders, 22 Fifth-graders

Step-by-step explanation:

126 third-graders

180 fourth-graders

198 fifth-graders

Find the highest common factor of 126, 180, 198

Factors of 126: 1, 2, 3, 6, 7, 9, 14, 18, 21, 42, 63, 126.

Factors of 180 : 1, 2, 3, 4, 5, 6, 9, 10, 12, 15, 18, 20, 30, 36, 45, 60, 90, 180

Factors of 198: 1, 2, 3, 6, 9, 11, 18, 22, 33, 66, 99, 198.

The highest common factor of 126, 180, 198 is 9

The largest possible number of teams that can be formed is 9

Each team has

third-graders = 126 / 9

= 14

Fourth-graders = 180 / 9

= 20

Fifth-graders = 198 divided by 9

= 22

There are 9 teams possible each having 14 third-graders, 20 Fourth-graders, 22 Fifth-graders

3 0
3 years ago
25 POINTS!!!!!!!!!!<br> Evaluate log7 343.<br><br> A. 49<br> B. 3<br> C. −3<br> D. −49
BlackZzzverrR [31]
<span>The answer to this problem is 3.      3^7 is equal to 343.</span>
5 0
3 years ago
Read 2 more answers
A target with a diameter of 14cm has 4 scoring zones by concentric circles. The diameter of the center circle is 2 cm. The width
Leni [432]

Answer:

48.98\%

Step-by-step explanation:

we know that

The probability that it will hit a point in the outer (yellow) ring is equal to divide the area of the yellow ring by the total area of the target

step 1

Find the area of the yellow ring

A=\pi [7^{2} -5^{2}]

A=24\pi\ cm^{2}

step 2

Find the total area of the target

A=\pi [7^{2}]

A=49\pi\ cm^{2}

step 3

Find the probability

24\pi/49\pi=0.4898

Convert to percentage

0.4898*100=48.98\%

4 0
3 years ago
Read 2 more answers
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