Question

How do you solve this?

Answer 1

You know all the angles in the triangle 30°, 60°, and 90°. To find the missing sides we will use:

$Sin\frac{opposite}{hypotenuse} Cos\frac{adjacent}{hypotenuse} Tan\frac{opposite}{adjacent}$ or $S\frac{O}{H} C\frac{A}{H} T\frac{O}{A}$

sin 60° = $\frac{O}{H}$

sin 60° = $\frac{x}{8\sqrt{3}}$

8√3(sin 60°) = x

8√3($\frac{\sqrt{3} }{2}$) = x

12 = x

cos 60° = $\frac{A}{H}$

cos 60° = $\frac{y}{8\sqrt{3} }$

8√3(cos 60°) = y

8√3($\frac{1}{2}$) = y

4√3 = y

Answer 2

Triginometry. Which side do you want to solve for?