1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
vaieri [72.5K]
4 years ago
7

2. An online bookstore sells both print books and e-books (books in an electronic format). Customers can pay with either a gift

card or a credit card.
a. Suppose that the probability of the event "print book is purchased" is 0.6 and that the probability of the event "customer pays using gift card" is 0.2. If these two events are
independent, what is the probability that a randomly selected book purchase is a print book paid for using a gift card?
b. Suppose that the probability of the event "e-book is purchased" is 0.4; the probability of the event "customer pays using gift card" is 0.2; and the probability of the event "e-book is
purchased and customer pays using a gift card" is 0.1. Are the two events "e-book is purchased" and "customer pays using a gift card" independent? Explain why or why not.
Mathematics
1 answer:
Fudgin [204]4 years ago
5 0

Answer:

a.0.12

b. Dependent

Step-by-step explanation:

a. The two events mentioned here are " print book is purchases" and "customer using gift card". P(P)=0.6 and P(C)=0.2. we have to calculate the probability of print book selection for purchase and payment is made through gift card i.e. P(P∩C). P(P∩C)=P(P)*P(C)=0.6*0.2=0.12.

b. If P(A∩B)=P(A)*P(B), then the two events are independent. Here in the given situation two independent variables are "purchase of e-book" and  "payment made using gift card"

P(E)=0.4

P(G)=0.2

P(E and G)=P(E∩G)=0.1

P(E)*P(G)=0.4*0.2=0.08 that is not equal to 0.1. So, the two events "e-book is purchased" and "Payment made by customer using gift card" are not independent.

You might be interested in
When a flash of lightning occurs, the number of seconds elapsed until thunder is heard can be used to approximate the distance f
inn [45]
Pretty sure its C :)
6 0
3 years ago
Read 2 more answers
A metal plate is 8.431 centimeters wide. Which is this measure written in word form?
vagabundo [1.1K]

Answer:

Eight and one hundred thirty-four thousandths

Step-by-step explanation:

Thats how u write it in word form! i hope this helped :)

6 0
3 years ago
If you triple 4 and subtract to each day how many days until you have zero
Mrrafil [7]
Do you mean subtract two each day? If so...
4x3=12 and 12 divided by 2 is 6 so it would take six days to reach zero
or
you could manually subtract two from 6 each days as in 12-2=10 (1 day), 10-2=8 (2 days), and so on...
5 0
3 years ago
Please help me with this question (:
fenix001 [56]

\frac{59  + x}{2}  = 78 \\ 59 + x = 156 \\ x = 97

Answer: VW=97

5 0
4 years ago
Molly buys a scooter for $63.00. and robert buys a soccer ball for $24.00.
goblinko [34]
All together they spend $87.00
5 0
3 years ago
Other questions:
  • Identify the transformation that carries the figure onto itself.
    9·1 answer
  • This Venn diagram represents the science subjects studied by students what is the probability chosen at random that that child d
    15·1 answer
  • P and Q each stand for whole numbers. P + Q = 1000 P is 150 greater than Q. Calculate the numbers P and Q ?
    5·1 answer
  • Please help!!!! Will give Brainliest!!!!!!!!!!!!!!!!!!
    8·1 answer
  • How do you evaluate fuctions?
    5·1 answer
  • Consider the following systems of rate of change equations:System A(dx/dt)= 3x(1-(x/10))- 20xy(dy/dt)= -5y+(xy/20)System B(dx/dt
    10·1 answer
  • Una caja de carton se ha disenado para qu contenga 184cm cubicos. Si su altura es de 10cm, cual es el area de la base?
    14·1 answer
  • The combined height of one fir tree and one pine tree is 212121 meters. The height of 444 fir trees stacked on top of each other
    6·2 answers
  • PLEASE HELP
    14·1 answer
  • -10 = y/11 -13 what is y
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!