CH3CI, CF4, HCI, NH3 which would have the lowest boiling point

Chemistry

2 answers:

german2 years ago

7 0

It’s CF4 at -198 degrees Fahrenheit

Sergio [31]2 years ago

6 0

Boiling point of a compound is determined by the strength of intermolecular forces of attraction between the molecules present in it. Stronger the intermolecular forces of attraction, higher will be the boiling point.

Ionic compounds show ion-ion interactions which are the strongest among all. Ion-dipole interactions are shown when ionic solutes are dissolved in polar solvents. Hydrogen bonding is also a relatively stronger force that is present between H atom and an electronegative atom like F, O and N( $NH_{3}$ ) . All polar molecules show dipole-dipole interaction ( $CH_{3}Cl$ and $HCl$ ). Dispersion forces are the weakest intermolecular forces due to momentary dipoles between electron clouds and nucleus.

Among the given compounds, $CF_{4}$ has dispersion forces as the major intermolecular forces of attraction. So they they exhibit the weakest IMF, hence have the lowest boiling point.

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stiv31 [10]

Answer: acetone is a ketone and not an aldehyde. Therefore it's false

Explanation:

Acetone is of structure CH3-CO-CH3

which makes it a ketone.

Both aldehyde and ketone have a carbonyl group but there is difference between aldehyde and ketone.

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where R is a methyl group including H atom, and CHO is the functional group.

While

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Hint: ketones usually end with the suffix "one" as in acetone.

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Paladinen [302]

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