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tatuchka [14]
3 years ago
7

What hazard classes are the following in?

Chemistry
2 answers:
Yakvenalex [24]3 years ago
3 0

Answer:

Idk maybe just look it up

Explanation:

zhuklara [117]3 years ago
3 0
I believe it’s
Uranium hexafluoride -7
Arsenic-6
Sulfuric acid -8
Dry ice -9
But let me know if I’m wrong
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Please help thank you
kondaur [170]

Answer:

C. The hand shears because their shorter handles transfer force more quickly to the cutting blade.

Explanation:

6 0
3 years ago
Read 2 more answers
What is the key difference between organic and inorganic molecules​
Naya [18.7K]

Answer:

See the answer below, please.

Explanation:

Organic compounds are those produced by living beings (molecules associated with living beings) and correspond to carbon compounds (the main difference with inorganic compounds). The latter are produced by natural processes or in the laboratory.

Example of organic products: alkanes (methane), alcohols (ethanol or ethyl alcohol)

Example of inorganic products: sodium hydroxide, sodium chloride

4 0
3 years ago
if the mass of a material is 119 grams and the volume of the material is 20 cm3, what would the density of the material be?
mixer [17]
M=D*V
D=m/V
m=119 g
V= 20 cm³
D=119 g/20 cm³ 
D= 5.95 g/cm³
6 0
3 years ago
What is the volume of a balloon containing 0.75 moles of gas at STP?
disa [49]

Answer:

V = 16.81 L

Explanation:

Given data:

Number of moles = 0.75 mol

Temperature = standard = 273 K

Pressure = 1 atm

Volume of balloon = ?

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

Now we will rearrange the formula.

V = nRT/P

V = 0.75 mol ×0.0821 atm.L/mol.K ×273 K / 1 atm

V = 16.81 atm.L/ 1 atm

V = 16.81 L

6 0
2 years ago
An unknown solid has a specific heat capacity of 0.727 J/gC. If a 12.3 grams sample is heated and increases in temperature from
WITCHER [35]

Answer:

355Joules

Explanation:

The amount of heat absorbed can be calculated using the formula:

Q = m × c × ∆T

Where;

Q = amount of heat absorbed in joules

m = mass of substance in grams

c = specific heat capacity of solid (0.727 J/g°C)

∆T = final temperature - initial temperature (°C)

According to the information provided in this question;

Q = ?

m = 12.3g

∆T = 62.1°C - 22.4°C = 39.7°C

c = 0.727 J/g°C

Using Q = m × c × ∆T

Q = 12.3 × 0.727 × 39.7

Q = 355.001

Q = 355Joules

Hence, 355J of heat was absorbed

8 0
2 years ago
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