Which of the following is the top view for the model?? Please help me

Which System has the same solution as the system of equation shown

Yuliya22 [10]

Answer: B. 8x+3y=5

-8x - 4y= -6

Step-by-step explanation:

The given system of equations is expressed as

8x + 3y =5 - - - - - - - - -1

4x + 2y =3 - - - - - - - - - - 2

We would eliminate x by multiplying equation 1 by 4 and equation 2 by 8. It becomes

32x + 12y =20

32x + 16y = 24

Subtracting, it becomes

- 4y = - 4

y = - 4/ - 4

y = 1

Substituting y = 1 into equation 1. It becomes

8x + 3 × 1 =5

8x + 3 = 5 - 3 = 2

x = 2/8 = 1/4

Substituting x = 1/4 and y = 1 into the given options, it becomes

A. 8 × 1/4 + 3 × 1=5

2 + 3 = 5

- 8 × 1/4 +4 × 1 = 2

B. 8x+3y=5

-8x - 4y= -6

- 8 × 1/4 - 4 × 1 = -6

Therefore, the system of of equations that has the same solution as the given equation is

B. 8x+3y=5

-8x - 4y= -6

4 0

4 years ago

To mail a letter to Vienna, Austria the post office charges a flat rate of $9.75 and an additional $0.50 for every ounce the let

bearhunter [10]

Missing details

Which type of function model would be appropriate for this situation?

Answer:

Linear function

Step-by-step explanation:

Given

$y = 0.50x +9.75$

Required

The function model

A function of the form:

$y = mx + b$

is referred to as a linear function where

$m = slope/rate$

$b=y\ intercept$

By comparison:

$m = 0.50\ b = 9.75$

<em>So, it is a linear function (linear model)</em>

4 0

3 years ago

What is the greatest common factor of 32,24,40

Mandarinka [93]

The GCF of 24, 32, and 80 must be 8, since it is the largest number common to both lists. Example 1 Find the greatest common factor of each set of numbers by listing factors.

8 0

3 years ago

A rectangular tank, 25 cm long and 25 cm wide is filled with water to a depth of 10 cm. When a metal cube of edge 10 cm is place

Sophie [7]

The problem involves the volume of the water of the rectangular tank, so first we must find the volume of our water. For the volume we have;

$\begin{gathered} \text{Volume = Lenght x Width x Height} \\ V_{water}_{}_{}\text{ = 25 x 25 x 10} \\ V_{water}=6250cm^3 \end{gathered}$

Therefore our tank has an initial volume of 6250 cm³, but if you drop a cube with a side measuring 10 cm. the volume of the water in our tank increases. Giving us the expression;

$\begin{gathered} \text{Volume Combined = Volume of Water + Volume of Cube} \\ V_{comb}=V_{water}+V_{cube} \end{gathered}$

Since we already have the volume of the water (which is 6250), we just need to find the volume of the cube using the same formula (<em>Volume = Lenght x Width x Height</em>);

$\begin{gathered} V_{comb}=V_{water}+V_{cube} \\ V_{comb}=V_{water}+(Lenght_{cube})(Width_{cube})(Height_{cube})_{}_{}_{} \\ V_{comb}=V_{water}+10(10)(10) \\ V_{comb}=6250+1000 \\ V_{comb}=7250cm^3 \end{gathered}$

Therefore our new volume when they are combined or when the cube is droped in the tank is 7250 cm³.

But we must remember since our tank would remain it's shape no matter how much water it holds it would always retain it's dimension of it's lenght and width (25x25), therefore it is possible to find the height of the new water level using this logic;

$\begin{gathered} V_{comb}=(Length_{\tan k})(Width_{\tan k})(Height_{water}\text{)} \\ V_{comb}=(25)(25)(Height_{water})\text{ , with our }V_{comb}=7250 \\ 7250=625(Height_{water}) \\ \text{Height}_{water}=\frac{7250}{625} \\ \text{Height}_{water}=11.6\text{ cm} \end{gathered}$

Therefore the height of the new water level is 11.6 cm.

7 0

1 year ago

a square field has an area of 2000 square feet. to the beat fest foot, how much fencing would be needed to enclose the field

swat32

Answer:

180 feet

Step-by-step explanation:

√2000 = 44.8

44.8 x 4 = 179.2 = 180 feet

5 0

4 years ago