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oksian1 [2.3K]
3 years ago
12

Which pair of complex factors results in a real numbeproduct? 15(–15i) 3i(1 – 3i) (8 + 20i)(–8 – 20i) (4 + 7i)(4 – 7i)

Mathematics
2 answers:
tiny-mole [99]3 years ago
7 0

Answer:

(4+7i)(4-7i).

This is because you FOIL it to get:

16 + 28i - 28i -49i^2.

That equals to 16 - 49i^2, which  equals to:

16 + 49

65, which is a real number.

svetlana [45]3 years ago
3 0

Answer:

D Is The Correct Answer

Step-by-step explanation:

(4+7i)(4-7i)

Your Welcome :)

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