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jenyasd209 [6]
3 years ago
10

 Define composite function.

Mathematics
1 answer:
frez [133]3 years ago
7 0
<span>Composition of Functions. Function Composition is applying one function to the results of another: The result of f() is sent through g() It is written: (g º f) (x)</span>
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Two cars leave towns 750 kilometers at the same time and travel toward each other. One car's rate is 12 kilometers per hour less
andreev551 [17]

If the distance between the two twons equals 750 km, and the cars met at some point on the road then the distance of the first car added to the distance of the second car equals 750 km, like this:

d1 + d2 = 750

Where d1 is the driven distance by the first car and d2 is the driven distance by the second car.

Distance, is the product of speed and time, then we can rewrite the above equation like this:

s1×t + s2×t = 750

S1 is the speed of the first car and s2 is the speed of the second time, t is the time. We already know that the time it took the cars to meet each other equals 5 hours, then, by replacing 5 for t into the above expression, we get:

s1×5 + s2×5 = 750

5(s1 + s2) = 750

We are also told that the speed of the first car is 12 less than the speed of the second car, this means that the speed of the first car equals the speed of the second one minus twelve. Then we can formulate the following expression for the speeds of the cars:

s1 = s2 - 12

By replacing s2 - 12 for s1 into 5(s1 + s2) = 750 we get:

5(s1 + s2) = 750

5(s2 - 12 + s2) = 750

5(s2 + s2 - 12) = 750

5(2s2 - 12) = 750

By dividing both sides by 5, we get:

(2s2 - 12) = 750/5

2s2 - 12 = 150

By adding 12 on both sides:

2s2 = 150 + 12

2s2 = 162

Finally, by dividing by 2 on both sides:

s2 = 162/2

s2 = 81

Now that we know that the speed of the second car, equals 81, we can find the speed of the first car by means of the formula s1 = s2 - 12, then we get:

s1 = s2 - 12

s1 = 81 - 12

s1 = 69

Then, the speed of the slower car equals 69 kilometers per hour

7 0
1 year ago
One bar of candy A and two bars of candy B have 777 calories. Two bars of candy A and one bar of candy B contain 783 calories. F
RSB [31]

Answer:

A has 263 calories

B has 257 calories

Step-by-step explanation:

system of equations:

a + 2b = 777

2a + b = 783

I multiplied the first equation by -2 to eliminate the 'a' terms

  -2a - 4b = -1554

+ <u> 2a  + b =    783</u>

         -3b = -771

b = 257

solve for 'a'

a + 2(257) = 777

a + 514 = 777

a = 263

4 0
3 years ago
If a = 5i - 6j and b = -2i + 4j , find -3a + 2b
gavmur [86]

Answer:

-19i + 26j

Step-by-step explanation:

-3 (5i - 6j) + 2 (-2i + 4j)

Distribute/multiply the -3 to everything in the parentheses

-15i + 18j + 2 (-2i + 4j)

Distribute/multiply the 2 to everything in the parentheses

-15i + 18j -4i + 8j

Combine like terms

-19i +26j

3 0
3 years ago
4.
matrenka [14]

Answer:

Step-by-step explanation:

D.works many year for a nation

8 0
2 years ago
Solve for x.<br> Your answer must be simplfied.<br><br> -7x &gt; 10
masha68 [24]

Answer:

3

Step-by-step explanation:

because its is like subtacting

7 0
2 years ago
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