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almond37 [142]
3 years ago
14

Find an equation of the plane. the plane through the point (3, −8, −4) and parallel to the plane 2x − y − z

Mathematics
1 answer:
Marina86 [1]3 years ago
6 0
Geggggggggggggggggggggggggggggggggggggggggggggggggggggggggggg like yuhh
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If you’re good with geometry can you help me?
Paladinen [302]

Answer:

a: AB is perpendicular to CD

b: AM is equal in length to BM

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uppose that 10% of the population is taking a certain drug, and 30% of them suffer from migraines as a side effect. Supposing th
blondinia [14]

Answer:LetAbe the event that the person is taking the drug. We are told thatP(A) = 0.05.LetBbe the event that the person has migraines. We are told thatP(B) = 0.1.Further, we are told thatP(B|A) = 0.3. Using the rules for conditional probability,P(A|B) =P(A∩B)P(B)=P(B|A)P(A)P(B)=0.3·0.050.1=0.15.The probability that a migraine sufferer takes the drug is 15%.

Step-by-step explanation:

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3 years ago
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What is the value of 2cos^2(75degrees) - 1?<br> Edge
Vinil7 [7]

Step-by-step explanation:

2(cos 75)(cos75) -1

=2(0.6699) -1

=1.3398-1

=0.3398

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2 years ago
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Help me plz thank you
DIA [1.3K]

Answer:C

Step-by-step explanation: 100 x 23/100=23

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3 years ago
Find r'(t), r(t0), and r'(t0) for the given value of (t0). r(t) = (e^t, e²t), t0 = 0​
creativ13 [48]

Applying the differentiation rule, it can be obtained that:

r'(t)=(e^t,2e^{2t}), r(t_0)=(1,1) and r'(t_0)=(1,2).

<h3>What is the formula for differentiating an exponential function?</h3>

The exponential function exists a mathematical function designated by f(x)=\exp or e^{x}. Unless otherwise determined, the term generally directs to the positive-valued function of a real variable, although it can be extended to complex numerals or generalized to other mathematical objects like matrices or Lie algebras.

In mathematics, the derivative of a function of a real variable estimates the sensitivity to change of the function value affecting a change in its statement. Derivatives exist as a fundamental tool of calculus.

\frac{d}{dt}(e^{mt})=me^{mt}.

Given that r(t)=(e^t,e^{2t}).

So, differentiating r(t)=(e^t,e^{2t}) with respect to t, we get: r'(t)=\left(\frac{d}{dt}(e^t),\frac{d}{dt}(e^{2t})\right).

So, using the above formula \frac{d}{dt}(e^{mt})=me^{mt}, we get: r'(t)=(e^t,2e^{2t}).

Now, substituting t=t_0=0 in r(t)=(e^t,e^{2t}) and r'(t)=(e^t,2e^{2t}), we obtain:

r(t_0=0)=(e^0,e^{2\times 0})=(1,1) and r'(t_0=0)=(e^0,2e^{2\times 0})=(1,2).

Therefore, applying the differentiation rule, we get:

r'(t)=(e^t,2e^{2t}), r(t_0)=(1,1) and r'(t_0)=(1,2).

To know about the differentiation rule, refer:

brainly.com/question/25081524

#SPJ9

5 0
11 months ago
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