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3 years ago

If anyone can tell me how to do 26 that would be great PLEASE SHOW WORK

Mathematics

1 answer:

katovenus [111]3 years ago

8 0

Hello from MrBillDoesMath!

Answer:

Discussion:

I stared at the numbers 19, 29, 39, 49, 59, 69,... for a second and noticed that adding 10 to any number gives the next number to the right. For example,

19 + 10 = 29

29 + 10 = 39

39 + 10 = 49

etc.....

A recursive formula would be:

a(0) = 19

a(n+1) = a(n) + 10 if n >= 0

Regards,

MrB

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Help help please!!

andrey2020 [161]

Answer:

1). y = -7/5x - 4

2). y = 1/5x - 5

Step-by-step explanation:

In this question, we have to write the slope-intercept form of the given information.

Slope intercept form is: y = mx + b

Our "m" value is our slope and our "b" value is our y-intercept.

With that knowledge, we can plug in our given information to the slope-intercept equation:

1) slope = -7/5, y-intercept = -4

Plug -7/5 to "m" and -4 to "b"

y = -7/5x - 4

2) slope = 1/5, y-intercept = -5

Plug 1/5 to "m" and -5 to "b"

y = 1/5x - 5

6 0

3 years ago

Evaluate.<br> 18.65 -52/11=

professor190 [17]

The answer is about 13.9927.

You would divide 52/11 and then subtract that decimal by 18.65.

18.65-4.7272=13.9927.

6 0

3 years ago

Evaluate the double integral.

Fynjy0 [20]

Answer:

$\iint_D 8y^2 \ dA = \dfrac{88}{3}$

Step-by-step explanation:

The equation of the line through the point $(x_o,y_o)$ & $(x_1,y_1)$ can be represented by:

$y-y_o = m(x - x_o)$

Making m the subject;

$m = \dfrac{y_1 - y_0}{x_1-x_0}$

∴

we need to carry out the equation of the line through (0,1) and (1,2)

i.e

y - 1 = m(x - 0)

y - 1 = mx

where;

$m= \dfrac{2-1}{1-0}$

m = 1

Thus;

y - 1 = (1)x

y - 1 = x ---- (1)

The equation of the line through (1,2) & (4,1) is:

y -2 = m (x - 1)

where;

$m = \dfrac{1-2}{4-1}$

$m = \dfrac{-1}{3}$

∴

$y-2 = -\dfrac{1}{3}(x-1)$

-3(y-2) = x - 1

-3y + 6 = x - 1

x = -3y + 7

Thus: for equation of two lines

x = y - 1

x = -3y + 7

i.e.

y - 1 = -3y + 7

y + 3y = 1 + 7

4y = 8

y = 2

Now, y ranges from 1 → 2 & x ranges from y - 1 to -3y + 7

∴

$\iint_D 8y^2 \ dA = \int^2_1 \int ^{-3y+7}_{y-1} \ 8y^2 \ dxdy$

$\iint_D 8y^2 \ dA =8 \int^2_1 \int ^{-3y+7}_{y-1} \ y^2 \ dxdy$

$\iint_D 8y^2 \ dA =8 \int^2_1 \bigg ( \int^{-3y+7}_{y-1} \ dx \bigg) dy$

$\iint_D 8y^2 \ dA =8 \int^2_1 \bigg ( [xy^2]^{-3y+7}_{y-1} \bigg ) \ dy$

$\iint_D 8y^2 \ dA =8 \int^2_1 \bigg ( [y^2(-3y+7-y+1)]\bigg ) \ dy$

$\iint_D 8y^2 \ dA =8 \int^2_1 \bigg ([y^2(-4y+8)] \bigg ) \ dy$

$\iint_D 8y^2 \ dA =8 \int^2_1 \bigg ( -4y^3+8y^2 \bigg ) \ dy$

$\iint_D 8y^2 \ dA =8 \bigg [\dfrac{ -4y^4}{4}+\dfrac{8y^3}{3} \bigg ]^2_1$

$\iint_D 8y^2 \ dA =8 \bigg [ -y^4+\dfrac{8y^3}{3} \bigg ]^2_1$

$\iint_D 8y^2 \ dA =8 \bigg [ -2^4+\dfrac{8(2)^3}{3} + 1^4- \dfrac{8\times (1)^3}{3}\bigg]$

$\iint_D 8y^2 \ dA =8 \bigg [ -16+\dfrac{64}{3} + 1- \dfrac{8}{3}\bigg]$

$\iint_D 8y^2 \ dA =8 \bigg [ -15+ \dfrac{64-8}{3}\bigg]$

$\iint_D 8y^2 \ dA =8 \bigg [ -15+ \dfrac{56}{3}\bigg]$

$\iint_D 8y^2 \ dA =8 \bigg [ \dfrac{-45+56}{3}\bigg]$

$\iint_D 8y^2 \ dA =8 \bigg [ \dfrac{11}{3}\bigg]$

$\iint_D 8y^2 \ dA = \dfrac{88}{3}$

4 0

2 years ago

Write the equation of the line with a slope of 3/2 that contains the point (-2,-4) .

VARVARA [1.3K]

Answer:

y= 3/2x- 4

Step-by-step explanation:

3/2 = mx

b= -4

y=mx+b

8 0

3 years ago

Suppose xy > 0. Describe the points whose coordinates are solutions to the inequality.

Elan Coil [88]

The solutions fo the inequality are all the points (x, y) that meet these 3 conditions.

x ≠ 0
y ≠ 0
Sign(x) =sign(y)

<h3>Which points are solutions of the inequality?</h3>

We want to find points of the form (x, y) that are solutions of the inequality:

x*y > 0

Clearly x and y must be different than zero.

So, for example if x = -1, y can be any negative number, for example y= -3

x*y > 0

(-1)*(-3) > 0

3 > 0

This is true.

Now if x = 1, y must be positive. LEt's take y = 103, then:

x*y > 0

1*103 > 0

103 > 0

Then we have 3 conditions:

x ≠ 0
y ≠ 0
Sign(x) =sign(y)

The solutions fo the inequality are all the points (x, y) that meet these 3 conditions.

If you want to learn more about inequalities:

brainly.com/question/25275758

#SPJ1

4 0

2 years ago