3 years ago

Which statement about an electron in the 4d state is correct?

Physics

1 answer:

Semenov [28]3 years ago

7 0

Answer:

Explanation:

i may be wrong but i think b??????????

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You drop a rock off of a cliff at exactly the edge after 25 seconds exactly you hear a splash your physics friend tells you the

Reptile [31]

The speed of sound is 340.29 meters per second.

Knowing that, we can calculate how high this cliff is by 340.29 * .4

The cliff is 340.29 * .4 = 136.12 meters

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4 years ago

Which term best describes the process that occurs when light passes through a lens? A. reflection B. refraction C. resonance D.

Elza [17]

A. Refraction, meaning the same thing...it just passes through. Reflection is when light, heat, or sound bounces off a surface, kind of like an echo. Resonance is sound reverberating, or vibrating. And polarization is the action of not allowing the vibrations of a transverse wave. Hoped this helps you :)

Short answer: Refraction

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3 years ago

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Suppose that an electric charge is produced on one part of a body. If the charge spreads through the entire body, the body is mo

timurjin [86]

C metal. most metals are a conductor which an electric current is attracted to.

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3 years ago

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.In real life, a given system can approach equilibrium from different starting points but will still have the same equilibrium c

Degger [83]

<span>It does not matter where the system starts but it will reach to an equilibrium state when the equilibrium ratio is reached.

hope it helps </span>

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3 years ago

The greatest height reported for a jump into an airbag is 99.4 m by stuntman Dan Koko. In 1948 he jumped from rest from the top

vaieri [72.5K]

Answer:

v = 44,16 m/s

Explanation:

We will fixate our reference in the starting point from where Dan jumped of, at the top of the Casino. Therefore, the displacement made when dan reached the airbag would be of y= -99,4 m viewed from our reference. We describe the motion of dan with the equation:

$v_y^2 =v_0^2 +2ay$

Dan jumped from the rest, that means that the initial velocity v_0=0, therefore:

$v_y^2 =2ay \rightarrow v_y = \sqrt{2ay}$

Since Dan is moving in the negative axis regarding our reference point, we take the negative root of the equation.

v_y=-√(2*(-9,81 m/s^2 )*(-99,4 m) )=44,1613 m/s $v_y =- \sqrt{2*(-9,81 m/s^2)*(-99,4 m)} = 44,1613 m$

So, if we don’t take the air resistance into account, Dan would have achieved an velocity of 44,16 m/s when he reached the airbag.

I hope everything was clear with my explanation. If you need anything else, let me know. Have a great day :D

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4 years ago