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shepuryov [24]
3 years ago
6

Which of the following is the final fate of a very massive star?

Chemistry
1 answer:
STatiana [176]3 years ago
8 0

D. Black holes

When a star dies out it explodes and causes a supernova and after a very long period of time the supernovas gasses vanish and the star can be visibly identified as a black hole!

You might be interested in
An aqueous solution of sucrose (C12H22O11C12H22O11) is prepared by dissolving 7.6330 gg in sufficient deionized water to form a
Mariana [72]

Answer:

The answer to your question is 0.64 M

Explanation:

Data

Sucrose C₁₂H₂₂O₁₁ mass = 7.633 g

volume = 25 ml

Molarity = ?

Process

1.- Calculate the molar weight of Sucrose

C₁₂H₂₂O₁₁ = (12 x 12) +(22 x 1) + (11 x 16)

                = 144 + 22 + 176

                = 342 g

2.- Calculate the moles of sucrose

                   342 g ------------------ 1 mol

                    7.633 g ---------------  x

                     x = (7.633 x 1) / 342

                    x = 0.0223 moles

3.- Calculate the molarity

Molarity = moles / volume (L)

Molarity = 0.0223 / 0.035

Molarity = 0.64

6 0
4 years ago
Estimate the Calorie content of 65 g of candy from the following measurements. A 15-g sample of the candy is placed in a small a
GrogVix [38]

Answer:

The calorie content of  65g of candy is 326.78 cal

Explanation:

Step 1: Data given

Mass of the candy = 15.00 grams

Mass of the container = 0.325 kg

Mass of water = 1.75kg

0.624 kg at an initial temperature of 15.0°C.

The specific heat of aluminium = 0.22 Cal/kg°C

The specific heat of water = 1 cal/kg°C

Step 2: Calculate calorie content for a 15 gram sample

ΔQ = Σm*c*ΔT

 ⇒ m = mass in grams

⇒ with c= the specific heat in Cal/kg°C

⇒ with ΔT = T2 -T1 = the change in temperatures in °C

ΔQ = m(bomb) * C(aluminium) * ΔT + m(cup) * C(aluminium) * ΔT + m(H2O) * c(H20) * ΔT

ΔQ = (m(bomb) + m(cup)) * c(aluminium)  + m(H2O)*c(H20) ) * ΔT

⇒ with mass of the bomb calorimeter = 0.325 kg

⇒ with mass of the cup = 0.624 kg

⇒ with c(aluminium) = the specific heat of aluminium = 0.22 Cal/kg°C

⇒ with mass of water = 1.75 kg

⇒ with c(water) = the heat capacity of water = 1 Cal/kg°C

⇒ with ΔT = the change in temperature = T2 - T1 = 53.5 - 15.0 = 38.5 °C

ΔQ = 0.325*0.22*38.5 + 0.624*0.22*38.5 + 1.75*1*38.5

ΔQ = ((0.325 + 0.624)*0.22 + 1.75*1)*38.5

ΔQ = 75.41 cal

Step 3: Calculate the calorie content for a 65 gram sample

For a 65g sample the calorie content will be more or less 4x higher than a 15 gram sample:

ΔQ = 75.41  * (65/15) = 326.78 cal

8 0
3 years ago
Chemical formula for sodium and sulfur
Nookie1986 [14]
The chemical formula for sodium and sulfur is Na2S I believe...
8 0
3 years ago
Please please help please
ivann1987 [24]

answer: A and C

Explanation:

i think its that because all you have to do is just think about it very slowey in it will just come to your head.

4 0
3 years ago
Helpp chemistry ..........
ValentinkaMS [17]
Half-life is the time it takes for the radioactive material's mass to decrease by half.

So, half of 96 is 48
half of 48 is 24
half of 24 is 12
half of 12 is 6

96->48->24->12->6

You count how many arrows (->) there is.
Which is 4

Then you use the 12 minutes the question gave you to do:
12 divided by 4
= 3

So, one half-life (Or the time it takes for the radioactive material's mass to decrease in half) is 3 minutes

and every 3 minutes it will decrease by half.
3 0
3 years ago
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