Answer:
The correct answer would be A.
Answer:
The answer to your question is
51.- 1.59 x 10⁻⁶
53.- NaHCO₃ + HCl ⇒ H₂O + CO₂ + NaCl
Explanation:
51.- Convert 0.00159 ml to liters
Use a rule of three
1000 ml -------------- 1 l
0.00159 ml --------- x
x = (0.00159 x 1) / 1000
x = 0.00000159 l = 1.59 x 10⁻⁶ l
53.- Sodium hydrogen carbonate (NaHCO₃) reacts with hydrochloric acid to produce salt, water and carbon dioxide.
Sodium hydrogen carbonate = NaHCO₃
Hydrochloric acid = HCl
Reaction
NaHCO₃ + HCl ⇒ H₂O + CO₂ + NaCl
water = H₂O
carbon dioxide = CO₂
salt = NaCl
Weeks = 6 x 4 = 24
Mass leak rate of freon = 41.60 g/week
Mass leak rate of fluorine
Fluorine mass in Freon
= —————————————- X leak rate
M.M. Of Freon
19 x 3
——— X 41.60 = 20.010 gm/week
118.5
Total leaked in 6 months
= 24 x 20.010 = 480.24 gm = 0.480 Kg
Answer:
6.56×10¹⁴ Hz
Explanation:
From the question given above, the following data were obtained:
Wavelength = 457 nm
Frequency =?
Next, we shall convert 457 nm to metre (m). This can be obtained as follow:
1 nm = 1×10¯⁹ m
Therefore,
457 nm = 457 nm × 1×10¯⁹ m / 1 nm
457 nm = 4.57×10¯⁷ m
Thus, 457 nm is equivalent to 4.57×10¯⁷ m
Finally, we shall determine the frequency of the blue light as follow:
Wavelength = 4.57×10¯⁷ m
Velocity of light = 3×10⁸ m/s
Frequency =?
Velocity = wavelength x frequency
3×10⁸ = 4.57×10¯⁷ × frequency
Divide both side by 4.57×10¯⁷
frequency = 3×10⁸ / 4.57×10¯⁷
frequency = 6.56×10¹⁴ Hz
Therefore, the frequency of the blue light is 6.56×10¹⁴ Hz
Answer:
See explanation below
Explanation:
First, let's write again the reaction:
CH₃COO⁻ + H(CH₃)₃N⁺ <-----------> CH₃COOH + (CH₃)₃N
Now that the reaction is here, let's remember the basis of the bronsted - lowry theory:
An acid (HA) is a substance that can lose a proton (Hydrogen atom) to form a conjugate base. A base is a substance that accepts the proton (Hydrogen) and form a conjugate acid.
According to this definition, let's see the reaction again.
In the reactants, we see the CH3COO and the H(CH3)N. and the products are CH3COOH and (CH3)3N. The difference? well, we can see that the CH3COO now has a Hydrogen atom, this means that the CH3COO accepted the Hydrogen; this hydrogen was provided by the H(CH3)3N.
Therefore, the acid in this reaction is the H(CH₃)₃N⁺ and the conjugate base will be the (CH₃)₃N
The base in this reaction is the CH₃COO⁻ while the conjugate acid will be the CH₃COOH
