Answer : The percent (by volume) of air displaced if all of the liquid nitrogen evaporated would be 29 %
Explanation :
Let us assume that 1.2 L container of liquid nitrogen is kept in a closet measuring 1.0m by 1.3m by 2.0m.
First we have to calculate the mass of nitrogen.

Given:
Density of nitrogen = 0.807 g/mL
Volume of nitrogen = 1.2 L = 1200 mL (1 L = 1000 mL)


Now we have to calculate the moles of nitrogen.

Molar mass of nitrogen
= 28 g/mole

Now we have to calculate the volume of nitrogen.
As we know that,
PV = nRT
where,
P = pressure of nitrogen = 1.1 atm
V = volume of nitrogen = ?
n = number of moles of nitrogen = 34.58 mole
R = gas constant = 0.0821 L.atm/mol.K
T = temperature of nitrogen = 
Now put all the given values in this formula, we get:


Now we have to calculate the volume of container.
The formula of volume of cuboid, we use the equation:

where,
V = volume of container = ?
l = length of container = 1.0 m
b = breadth of container = 1.3 m
h = height of container = 2.0 m
Putting values in above equation, we get:

Conversion used : 
Now we have to calculate the percent (by volume) of air that would be displaced if all of the liquid nitrogen evaporated.

Therefore, the percent (by volume) of air displaced if all of the liquid nitrogen evaporated would be 29 %