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Murljashka [212]
3 years ago
13

7y-9=3y+19. Need help

Mathematics
2 answers:
CaHeK987 [17]3 years ago
8 0

Answer: y = 7.

Step-by-step explanation:

First you need to combine like terms. The like terms in this is 7y & 3y and -9 & 19. So to combine those like terms, you first need to subtract 3y on both sides because to cancel out the 3y in the right side, you need to perform the opposite operation on the positive 3. And 3y - 3y is 0 so thats why you subtract 3y on both sides. When you subtract 3y from 7y on the left side (because 3y is the like term of 7y and what operation you do on one side you have to do on the other side of the equation) you get 4y - 9 = 19. Now you still need to combine the like terms -9 and 19 so you need to add 9 on both sides to get 4y = 28. Since 4 is being multiplied by "y" to get "y" by itself in the left side of the equation, you need to divide 4 on both sides. 28 ÷ 4 = 7, so your final answer would be y = 7!

I hope this is helpful :)

alexgriva [62]3 years ago
3 0

Answer:

y=7

Step-by-step explanation:

7y-3y=19+9

4y=28

y=7

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Two boats leave a dock at the same time. One boat travels south at 32 mi divided by hr32 mi/hr and the other travels east at 60
TEA [102]

Answer: the rate at which the distance between the boats is​ increasing is 68 mph

Step-by-step explanation:

The direction of movement of both boats forms a right angle triangle. The distance travelled due south and due east by both boats represents the legs of the triangle. Their distance apart after t hours represents the hypotenuse of the right angle triangle.

Let x represent the length the shorter leg(south) of the right angle triangle.

Let y represent the length the longer leg(east) of the right angle triangle.

Let z represent the hypotenuse.

Applying Pythagoras theorem

Hypotenuse² = opposite side² + adjacent side²

Therefore

z² = x² + y²

To determine the rate at which the distances are changing, we would differentiate with respect to t. It becomes

2zdz/dt = 2xdx/dt + 2ydy/dt- - - -- - -1

One travels south at 32 mi/h and the other travels east at 60 mi/h. It means that

dx/dt = 32

dy/dt = 60

Distance = speed × time

Since t = 0.5 hour, then

x = 32 × 0.5 = 16 miles

y = 60 × 0.5 = 30 miles

z² = 16² + 30² = 256 + 900

z = √1156

z = 34 miles

Substituting these values into equation 1, it becomes

2 × 34 × dz/dt = (2 × 16 × 32) + 2 × 30 × 60

68dz/dt = 1024 + 3600

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dz/dt = 4624/68

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Slope of 1,-7 and -3-4​
3241004551 [841]

\large \mathfrak{Solution : }

Slope of the given line is :

  • \dfrac{y_2 - y_1}{x_2 - x_1}

where ,

  • x_2 = 1

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  • y_1 =   - 4

let's solve :

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Slope = -3 / 4

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Write the slope-intercept form of the equation of the line described. 8.) through: ( -4 , 5 ) , perpendicular to Y= 3/2x - 2
kozerog [31]

Answer

The equation of the required line in slope-intercept form is

y = (-2x/3) + (7/3)

Comparing this with y = mx + c,

Slope = m = (-2/3)

Intercept = c = (7/3)

Explanation

The slope and y-intercept form of the equation of a straight line is given as

y = mx + c

where

y = y-coordinate of a point on the line.

m = slope of the line.

x = x-coordinate of the point on the line whose y-coordinate is y.

c = y-intercept of the line.

So, to solve this, we have to solve for the slope and then write the eqution in the slope-point form which we can then simplify to the slope-intercept form

The general form of the equation in point-slope form is

y - y₁ = m (x - x₁)

where

y = y-coordinate of a point on the line.

y₁ = This refers to the y-coordinate of a given point on the line

m = slope of the line.

x = x-coordinate of the point on the line whose y-coordinate is y.

x₁ = x-coordinate of the given point on the line

The point is given as (x₁, y₁) = (-4, 5)

Then, we can calculate the slope from the information given

Two lines with slopes (m₁ and m₂) that are perpendicular to each other are related through

m₁ × m₂ = -1

From the line given,

y = (3/2)x - 2

We can tell that m₁ = (3/2), so, we can solve for m₂

(3/2) (m₂) = -1

m₂ = (2/3) (-1) = (-2/3)

We can then write the equation of the given line in slope-intercept form

y - y₁ = m (x - x₁)

y - 5 = (-2/3) (x - (-4))

y - 5 = (-2/3) (x + 4)

y - 5 = (-2x/3) - (8/3)

y = (-2x/3) - (8/3) + 5

y = (-2x/3) + (7/3)

Hope this Helps!!!

4 0
1 year ago
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