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Pavel [41]
3 years ago
13

Differentiate the function

%7Bx%7D%20" id="TexFormula1" title="7 {x}^{3} + x \div 6 \sqrt{x} " alt="7 {x}^{3} + x \div 6 \sqrt{x} " align="absmiddle" class="latex-formula">
Physics
1 answer:
irakobra [83]3 years ago
4 0

There are two likely interpretations for the given function:

f(x)=7x^3+\dfrac x{6\sqrt x}

in which case you can write

\dfrac x{6\sqrt x}=\dfrac x{6x^{1/2}}=\dfrac16x^{1/2}

and the derivative is

f'(x)=21x^2+\dfrac1{12}x^{-1/2}=21x^2+\dfrac1{12\sqrt x}

Or, perhaps it is

f(x)=\dfrac{7x^3+x}{6\sqrt x}=\dfrac76x^{5/2}+\dfrac16x^{1/2}

\implies f'(x)=\dfrac{35}{12}x^{3/2}+\dfrac1{12\sqrt x}

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