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2 years ago

What would happen if the difference between the earth and moon decreased?

1 answer:

5 0

Now, moving the Moon closer to the Earth will increase the gravitational exertion of the satellite onto our planet. If the satellite were slightly closer, the tidal bulge would grow. Low tideswould be lower and high tideswould be higher and any low lying coastline would be flooded.

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Starting from rest, a particle that is confined to move along a straight line is accelerated at a rate of 5.0 m/s2. Which one of

Elanso [62]

Answer:

c) The slope is not constant and increases with increasing time.

Explanation:

The equation for the position of this particle (starting from rest is)

$s = at^2/2 = 5t^2/2 = 2.5t^2$

We can take derivative of this with respect to time t to get the equation of slope:

$s' = (2.5t^2)' = 2*2.5t = 5t$

As time t increase, the slope would increases with time as well.

6 0

3 years ago

What characteristics of matter he was studying

Levart [38]

Answer:

The main physical characteristics of matter are mass, volume, weight, density, odor, and color. These are the characteristics that help us to see matter, feel matter, and taste matter.

Explanation:

5 0

3 years ago

A soccer ball moving with an initial speed of 1.8 m/s is kicked with a

vova2212 [387]

Answer:

7.0 m

Explanation:

Step 1: Given data

Initial speed of the ball (u): 1.8 m/s

Acceleration (a): 6.1 m/s²

Final speed of the ball (v): 9.4 m/s

Step 2: Calculate the displacement (s) of the ball

The ball is moving with a uniformly accelerated rectilinear motion. We can calculate the displacement using the following suvat equation.

v² = u² + 2 × a × s

s = (v² - u²)/2 × a

s = [(9.4 m/s)² - (1.8 m/s)²]/2 × 6.1 m/s²

s = 7.0 m

7 0

2 years ago

What to forces effects the momentum of an object

faltersainse [42]

Any force can affect the momentum of an object
if it changes the object's speed.

4 0

3 years ago

Read 2 more answers

In an internal combustion engine, air at atmostpheric

notsponge [240]

Answer:

1302 K or 1029 C

Explanation:

Air at atmospheric pressure has pressure of 1 atm

20 C = 20 + 273 = 293 K

Assume ideal gas, according to the ideal gas law:

$\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}$

Where P1, V1 and T1 are the pressure, volume and temperature of the gas before the compression and P2, V2 and T2 are the pressure, volume and temperature of the gas after the compression

$T_2 = T_1\frac{P_2V_2}{P_1V_1}$

Since the gas is compressed to 1/9 of its original volume, V2/V1 = 1/9:

$T_2 = 293\frac{40}{9} = 1302 K$ or 1029 C

8 0

3 years ago