А A pool of water of refractive index
1 answer:
Answer:
Apparent depth = 45 cm
Explanation:
The refractive index of water in a pool, n = 4/3
Real depth, d = 60 cm
We need to find its apparent depth when viewed vertically through air. The ratio of real depth to the apparent depth is equal to the refractive index of the material. Let the apparent depth is d'. So,
So, the apparent depth is 45 cm.
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Answer:
The person on Earth will have to exert more force to lift their block
Explanation:
The mass of the blocks to be lifted = 200 kg
The location of the first person = On Earth
The location of the second person = On the Moon
The force a person will have to exert to lift the block = The weight of the block = The gravitational force, F, on the block which is given as follows;
Where;
= The acceleration due to gravity on the Earth or the Moon, depending on the location of the block
m₂ = The mass of the block
Therefore, given that the acceleration due to gravity on the Earth is larger than the acceleration due to gravity on the Moon, the weight of the block on the Earth is larger than the weight of the block on the Moon, and the person on Earth have to exert more force to lift the heavier weight of the block on Earth than the person on the Moon will have to exert to lift the same block as the block has a lower weight on the Moon due to lower acceleration due to gravity on the Moon.
Answer:
The acceleration of rocket B is -22.24 m/s²
Explanation:
Two rockets are flying in the same direction and are side by side at the
instant their retrorockets fire
That means they started from the same point at the same time
Rocket A has an initial velocity of 5800 m/s
Rocket B has an initial velocity of 8600 m/s
After a time t both rockets are again side by side, the displacement of
each being zero
That means they are in the same position again → s = 0
The acceleration of rocket A is -15 m/s²
We need to find the acceleration for rocket B
We can find the time from the information of rocket A by using the
rule → s = u t + a t²
where s is the displacement, u is the initial velocity, a is the
acceleration, and t is the time
→ s = 0 , u = 5800 m/s , a = -15 m/s²
Substitute these values in the rule
→ 0 = 5800 t + (-15) t²
→ 0 = 5800 t - 7.5 t²
Add 7.5 t² for both sides
→ 7.5 t² = 5800 t
Divide both sides by 7.5 t
→ t = 773.3 s
The time for the both rocket to have displacement zero is 773.3 s
Now we can find the acceleration of the rocket B by using the same
rule above
→ u = 8600 m/s , t = 773.3 , s = 0
→ 0 = (8600)(773.3) + a (773.3)²
→ 0 = 6650380 + 298996.445 a
Subtract 6650380 from both sides
→ -6650380 = 298996.445 a
Divide both sides by 298996.445
→ a = -22.24 m/s²
<em>The acceleration of rocket B is -22.24 m/s²</em>