Answer:
See the answers below
Explanation:
In this problem, we must be clear about the concept of weight. Weight is defined as the product of mass by gravitational acceleration.
We must be clear that the mass is always preserved, that is, the mass of 15 [kg] will always be the same regardless of the planet where they are.
where:
W = weight [N] (units of Newtons)
m = mass = 15 [kg]
g = gravity acceleration [m/s²]
Since we have 9 places with different gravitational acceleration, then we calculate the weight in each of these nine places.
<u>Mercury</u>
<u />![w_{mercury} = 15*3.8\\w_{mercury}= 57 [N]\\](https://tex.z-dn.net/?f=w_%7Bmercury%7D%20%3D%2015%2A3.8%5C%5Cw_%7Bmercury%7D%3D%2057%20%5BN%5D%5C%5C)
<u />
<u>Venus</u>
<u />![w_{venus}=15*8.8\\w_{venus}= 132 [N]](https://tex.z-dn.net/?f=w_%7Bvenus%7D%3D15%2A8.8%5C%5Cw_%7Bvenus%7D%3D%20132%20%5BN%5D)
<u />
<u>Moon</u>
<u />![w_{moon}=15*1.6\\w_{moon}=24[N]](https://tex.z-dn.net/?f=w_%7Bmoon%7D%3D15%2A1.6%5C%5Cw_%7Bmoon%7D%3D24%5BN%5D)
<u />
<u>Mars</u>
![w_{mars}=15*3.7\\w_{mars}=55.5 [N]](https://tex.z-dn.net/?f=w_%7Bmars%7D%3D15%2A3.7%5C%5Cw_%7Bmars%7D%3D55.5%20%5BN%5D)
<u>Jupiter</u>
<u />![w_{jupiter}=15*23.1\\w_{jupiter}= 346.5[N]](https://tex.z-dn.net/?f=w_%7Bjupiter%7D%3D15%2A23.1%5C%5Cw_%7Bjupiter%7D%3D%20346.5%5BN%5D)
<u />
<u>Saturn</u>
<u />![w_{saturn}=15*9\\w_{saturn}=135[N]](https://tex.z-dn.net/?f=w_%7Bsaturn%7D%3D15%2A9%5C%5Cw_%7Bsaturn%7D%3D135%5BN%5D)
<u />
<u>Uranus</u>
<u />![w_{uranus}=15*8.7\\w_{uranus}=130.5[N]](https://tex.z-dn.net/?f=w_%7Buranus%7D%3D15%2A8.7%5C%5Cw_%7Buranus%7D%3D130.5%5BN%5D)
<u />
<u>Neptune</u>
<u />![w_{neptune}=15*11\\w_{neptune}=165[N]](https://tex.z-dn.net/?f=w_%7Bneptune%7D%3D15%2A11%5C%5Cw_%7Bneptune%7D%3D165%5BN%5D)
<u />
<u>Pluto</u>
<u />![w_{pluto}=15*0.6\\w_{pluto}=9[N]](https://tex.z-dn.net/?f=w_%7Bpluto%7D%3D15%2A0.6%5C%5Cw_%7Bpluto%7D%3D9%5BN%5D)
<u />
Answer:
r = 2.031 x 10⁶ m = 2031 km
Explanation:
In order for the asteroid to orbit the planet, the centripetal force must be equal to the gravitational force between asteroid and planet:
Centripetal Force = Gravitational Force
mv²/r = GmM/r²
v² = GM/r
r = GM/v²
where,
r = radial distance = ?
G = Universal Gravitational Constant = 6.67 x 10⁻¹¹ N.m²/kg²
M = Mass of Planet = 3.52 x 10¹³ kg
v = tangential speed = 0.034 m/s
Therefore,
r = (6.67 x 10⁻¹¹ N.m²/kg²)(3.52 x 10¹³ kg)/(0.034 m/s)²
<u>r = 2.031 x 10⁶ m = 2031 km</u>
If a car crashes into another car like this, the wreck should go nowhere. Besides this being an unrealistic question, the physics of it would look like this:
Momentum before and after the collision is conserved.
Momentum before the collision:
p = m * v = 50000kg * 24m/s + 55000kg * 0m/s = 50000kg * 24m/s
Momentum after the collision:
p = m * v = (50000kg + 55000kg) * v
Setting both momenta equal:
50000kg * 24m/s = (50000kg + 55000kg) * v
Solving for the velocity v:
v = 50000kg * 24m/s/(50000kg + 55000kg) = 11,43m/s
7kinetic energy is decreasing in B
