A quantity y is to be determined from the equation y=(px)/q^2
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Answer:
The net force acting on the person is 5.34 N acting upwards
Explanation:
The information given are;
Mass of the person = 55.0 kg
Density of the person = 1010 kg/m³
Body volume of the person = Mass/Density = 55/1010 = 0.0545 m³
Weight of the person = Mass × Gravity = 55 × 9.81 = 539.55 N↓
Where the density of water = 1000 kg/m³, we have;
Upthrust = weight of the water displaced = Mass of the water displaced × Gravity
Mass of the water displaced = Density of water × Volume of the water
Mass of the water displaced = Density of water × Body volume of the person
= 1000 × 0.0545 = 54.5 kg
The Upthrust = 54.5 × 9.81 = 534.21 N↑
Given that the net force, acting is the sum of the mass of forces acting on the person which are the weight acting downward and the upthrust acting upwards
We have;
F(Net) = 534.21↑ - 539.55↓ = 5.34 N↑
The net force acting on the person = 5.34 N upwards.