Name the type of particle formed by covalent bonds
1 answer:
You might be interested in
Missing data: the wave number
(a)
For a transverse wave travelling in the positive y-direction and with vibration along the z-direction, the equation of the wave is
where
A is the amplitude of the wave
k is the wave number
is the angular frequency
t is the time
In this situation:
A = 3.0 mm = 0.003 m is the amplitude
is the wave number
is the period, so the angular frequency is
So, the wave equation (in meters) is
(b) 0.094 m/s
For a transverse wave, the transverse speed is equal to the derivative of the displacement of the wave, so in this case:
So the maximum transverse wave occurs when the cosine term is equal to 1, therefore the maximum transverse speed must be
where
Substituting,
(c) 5.24 mm/s
The wave speed is given by
where
f is the frequency of the wave
is the wavelength
The frequency can be found from the angular frequency:
While the wavelength can be found from the wave number:
Therefore, the wave speed is
Answer:
λ = 451.7 nm
Explanation:
The expression for the constructive interference of the double diffraction experiment is
d sin θ = m λ
let's use trigonometry
tan θ = y / L
how the experiment occurs at very small angles
tan θ = sin θ / cos θ = sin θ
sin θ = y / L
we substitute
d y / L = m λ
λ =
let's calculate
λ =
λ = 4.51699 10⁻⁷ m
λ = 4.517 10⁻⁷ m (109 nm / 1m)
λ = 451.7 nm