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irga5000 [103]
3 years ago
9

Which instrument is launched into the atmosphere to collect pressure, temperature, humidity, wind speed, and other data?

Physics
1 answer:
koban [17]3 years ago
5 0
C. Radiosonde is the answer

the above mentioned is not correct
You might be interested in
Please help!
julsineya [31]

Answer:

Answer:

3 g/cm          

Explanation:

Mass of stone = 30 g

Initial volume of cylinder = 50 cm

Increased volume = 60 cm

Volume = 60-50

= 10 cm

Density of stone = Mass/Volume

= 30/10

= 3 g/ml            as 1 ml = 1 cm

= 3 g/ml          

Explanation:

6 0
2 years ago
Please answer help me
Andrews [41]
I believe the answer is x
7 0
2 years ago
The y-component of the force F which a person exerts on the handle of the box wrench is known to be 70 lb. Determine the x-compo
Yuri [45]

Answer:

<em>Fx = 121.24lb</em>

<em>F = 140lb</em>

Explanation:

Since we are not given the angles subtended by the force, we can assume it to be 30 degrees.

The y component of the force expressed by the formula:

Fy = Fsintheta

Given the y-component of the force F to bee 70lb

70lb =  Fsintheta

Get magnitude of the force

F = 70/sin theta

F = 70/sin 30

F = 70/0.5

F = 140lb

Get the x-component of the force

Fx = Fcos theta

Fx = 140cos 30

Fx = 140(0.8660)

Fx = 1,212.4lb

<em>Hence the  x-component of the force sis 121.24lb</em>

<em></em>

<em>Note that the angle used was assumed. Other values can as well be used</em>

5 0
2 years ago
What is used to measure the speed of a moving vehicle along the road​
Romashka [77]

Answer:

Speedometer

Explanation:

Speedometer

8 0
2 years ago
Read 2 more answers
A gas bottle contains 0.650 mol of gas at 730 mm Hg pressure. If the final pressure is 1.15 atm, how many moles of gas were adde
AlekseyPX

Answer:

0.779 mol

Explanation:

Since the gas is in a bottle, the volume of the gas is constant. Assuming the temperature remains constant as well, then the gas pressure is proportional to the number of moles:

p \propto n

so we can write

\frac{p_1}{n_1}=\frac{p_2}{n_2}

where

p1 = 730 mm Hg = 0.96 atm is the initial pressure

n1 = 0.650 mol is the initial number of moles

p2 = 1.15 atm is the final pressure

n2 is the final number of moles

Solving for n2,

n_2 = n_1 \frac{p_2}{p_1}=(0.650 mol)\frac{1.15 atm}{0.96 atm}=0.779 mol

6 0
3 years ago
Read 2 more answers
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