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irga5000 [103]
3 years ago
9

Which instrument is launched into the atmosphere to collect pressure, temperature, humidity, wind speed, and other data?

Physics
1 answer:
koban [17]3 years ago
5 0
C. Radiosonde is the answer

the above mentioned is not correct
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The distance around the block is equal to 3000 feet, how many blocks would you have to run to run a total of a mile?
lesya692 [45]
You would have to run a little less than 2 blocks
7 0
3 years ago
A 6.00 A current runs through a 12-gauge copper wire (diameter 2.05 mm) and through a light bulb. Copper has 8.5×1028 free elect
navik [9.2K]

Answer:

Explanation:

Current, I = 6 A

diameter of wire, d = 2.05 mm

number of electrons per unit volume, n = 8.5 x 10^28

If the diameter is doubled,

The resistance of the wire is inversely proportional to the square of the diameter of the wire, so the resistance is  one forth an the current is directly proportional to the diameter of the wire so the current is four times the initial value.  

8 0
3 years ago
A harmonic wave is traveling along a rope. It is observed that the oscillator that generates the wave completes 37.0 vibrations
Goryan [66]

Answer:

0.47 m

Explanation:

N = Number of vibrations = 37

t = total time taken = 33 s

T = time period of each vibration

frequency of vibration is given as

f = \frac{N}{t} \\f = \frac{37}{33} \\f = 1.12 Hz

d = distance traveled along the rope = 421 cm = 4.21 m

t = time taken to travel the distance = 8 s

v = speed of the wave

Speed of the wave is given as

v = \frac{d}{t}\\v = \frac{4.21}{8}\\v = 0.53 ms^{-1}

\lambda = wavelength of the harmonic wave

wavelength of the harmonic wave is given as

\lambda = \frac{v}{f} \\\lambda = \frac{0.53}{1.12} \\\lambda = 0.47 m

8 0
3 years ago
Read 2 more answers
Definition of AM and Fm Wave? in your own word
vfiekz [6]

Answer:

In AM broadcasting, the amplitude of the carrier wave is modulated to encode the original sound. In FM broadcasting, the frequency of the carrier wave is modulated to encode the sound. A radio receiver extracts the original program sound from the modulated radio signal and reproduces the sound in a loudspeaker.

8 0
3 years ago
A 15.0 Ohms resistor is connected in series to a 120V generator and two 10.0 Ohms resistors that are connected in parallel to ea
Nostrana [21]

Hi there! :)

Reference the diagram below for clarification.

1.

We must begin by knowing the following rules for resistors in series and parallel.

In series:
R_T = R_1 + R_2 + ... + R_n

In parallel:
\frac{1}{R_T} = \frac{1}{R_1} + \frac{1}{R_2} + ... + \frac{1}{R_n}

We can begin solving for the equivalent resistance of the two resistors in parallel using the parallel rules.

\frac{1}{R_{T, parallel}} = \frac{1}{10} + \frac{1}{10}\\\\\frac{1}{R_{T, parallel}} = \frac{2}{10} = \frac{1}{5}\\\\R_{T, parallel} = 5\Omega

Now that we have reduced the parallel resistors to a 'single' resistor, we can add their equivalent resistance with the other resistor in parallel (15 Ohm) using series rules:
R_T = 15 + 5\\\\\boxed{R_T = 20 \Omega}

2.

We can use Ohm's law to solve for the current in the circuit.

i = \frac{V}{R_T}\\\\i = \frac{120}{20} = \boxed{6 A}

3.

For resistors in series, both resistors receive the SAME current.

Therefore, the 15Ω resistor receives 6A, and the parallel COMBO (not each individual resistor, but the 5Ω equivalent when combined) receives 6A.

In this instance, since both of the resistors in parallel are equal, the current is SPLIT EQUALLY between the two. (Current in parallel ADDS UP). Therefore, an even split between 2 resistors of 6 A is <u>3A for each 10Ω resistor</u>.

4.

Since the 15.0 Ω resistor receives 6A, we can use Ohm's Law to solve for voltage.

V = iR\\\\V = (6)(15) = \boxed{90 V}

4 0
2 years ago
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