The answer to the equation is X= 27
Answer:
Step-by-step explanation:
Let the solution to
2x^2 + x -1 =0
x^2+ (1/2)x -(1/2)
are a and b
Hence a + b = -(1/2) ( minus the coefficient of x )
ab = -1/2 (the constant)
A. We want to have an equation where the roots are a +5 and b+5.
Therefore the sum of the roots is (a+5) + (b+5) = a+ b +10 =(-1/2) + 10 =19/2.
The product is (a+5)(b+5) =ab + 5(a+b) + 25 = (-1/2) + 5(-1/2) + 25 = 22.
So the equation is
x^2-(19/2)x + 22 =0
2x^2-19x + 44 =0
B. We want the roots to be 3a and 3b.
Hence (3a) + (3b) = 3(a+b) = 3(-1/2) =-3/2 and
(3a)(3b) = 9(ab) =9(-1/2)=-9/2.
So the equation is
x^2 +(3/2) x -9/2 = 0
2x^2 + 3x -9 =0.
Answer:
X=2
Step-by-step explanation:
hope this helps
Answer:
The value of the sum of n and -1=5
Step-by-step explanation:
Step 1
Get the value of n using the equation below;
The sum of n and 4 is 10 can be expressed in equation form as follows;
n+4=10...equation 1
solving for n;
n=10-4
n=6
The value for n=6
Step 2
Express the sum of n and -1 as follows
n+(-1)=unknown...equation 2
using the value of n solved in equation 1 in equation 2
replace using;
n=6
6+(-1)=6-1=5
The value of the sum of n and -1=5
<h3><u>Part A: An equation to represent this situation, where x represents the original length of the rectangle is:</u></h3>
<h3><u>Part B: Original length of the rectangle is 12 inches</u></h3>
<em><u>Solution:</u></em>
Given that,
A rectangle has a width of 2.5
Therefore,
width = 2.5 inches
Let "x" be the original length of the rectangle
When the length of this rectangle is decreased by 5 inches
Therefore,
New length = x - 5
The new area of the rectangle is 17.5 square inches
Therefore,
<em><u>The area of rectangle is given as:</u></em>
Thus original length of the rectangle is 12 inches
