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rewona [7]
3 years ago
7

Find the rational zeros and then the other zeros of the polynomial fraction f(x)=x^3+2x^2-3x-6 that is,solve f(x)=0

Mathematics
1 answer:
Salsk061 [2.6K]3 years ago
6 0

Hello from MrBillDoesMath!

Answer:

x = -2 and  x = +\- sqrt(3)


Discussion:  

x^3 + 2x^2 -3x -6 =   (x + 2) (x^2 - 3)

so the roots are x = -2 and x = +\- sqrt(3)



Regards,  

MrB

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