Question

Find the rational zeros and then the other zeros of the polynomial fraction f(x)=x^3+2x^2-3x-6 that is,solve f(x)=0

Answer 1

Hello from MrBillDoesMath!

Answer:

x = -2 and  x = +\- sqrt(3)

Discussion:  

x^3 + 2x^2 -3x -6 =   (x + 2) (x^2 - 3)

so the roots are x = -2 and x = +\- sqrt(3)

Regards,  

MrB