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larisa [96]
3 years ago
11

What state of matter takes the shape and volume of its container, like the steam coming from a pot A) gas B) liquid Eliminate C)

plasma D) solid
Physics
2 answers:
Gnoma [55]3 years ago
6 0

Ummm gas takes the shape and volume of its container, but I don't know about plasma. Solids definitely don't, and liquids don't change their volumes. So I would say gas. :)

BARSIC [14]3 years ago
4 0

It said “like the steam coming from a pot” which probably means it’s A) gas
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How can you tell whether something has kinetic energy?
Bond [772]
<h2>If the object is moving then it has kinetic energy</h2>
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Determine the distance from the Earth's center to a point outside the Earth where the gravitational acceleration due to the Eart
Temka [501]

The distance from the Earth's center to the point outside the Earth is 55800 Km

<h3>How to determine the distance from the surface of the Earth</h3>
  • Acceleration due to gravity of Earth = 9.8 m/s²
  • Acceleration due to gravity of the poin (g) = 1/60 × 9.8 = 0.163 m/s²
  • Gravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²
  • Mass of the Earth (M) = 5.97×10²⁴ Kg
  • Distance from the surface of the Earth (r) =?

g = GM / r²

Cross multiply

GM = gr²

Divide both sides by g

r² = GM / g

Take the square root of both sides

r = √(GM / g)

r = √[(6.67×10¯¹¹ × 5.97×10²⁴) / 0.163)]

r = 4.94×10⁷ m

Divide by 1000 to express in Km

r = 4.94×10⁷ / 1000

r = 4.94×10⁴ Km

<h3>How to determine the distance from the center of the Earth</h3>
  • Distance from the surface of the Earth (r) = 4.94×10⁴ Km
  • Radius of the Earth (R) = 6400 Km
  • Distance from the centre of the Earth =?

Distance from the centre of the Earth = R + r

Distance from the centre of the Earth = 6400 + 4.94×10⁴

Distance from the centre of the Earth = 55800 Km

Learn more about gravitational force:

brainly.com/question/21500344

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5 0
2 years ago
What is the name of the perceived change in a sound wave’s frequency due to motion between the observer and the sound source?
Scrat [10]

when observer and source moves relative to each other then the frequency received by the observer is different from the real frequency

This apparent change in frequency due to relative motion is known as Doppler's effect.

Here we know that

f_{app} = f_o\frac{v\pm v_o}{v \pm v_s}

here we know that

f_o = real frequency

v = speed of sound

v_o = speed of observer

v_s = speed of source

so this is known as Doppler's Effect

6 0
4 years ago
Read 2 more answers
What frequency is received by the ambulance after reflecting from a wall near the person watching the oncoming ambulance (as in
ElenaW [278]

Answer:

f=896Hz

Explanation:

Given data

Vs(speed of the ambulance)={(104 km/h)*(1000m*(1 h/3600)}=28.9m/s

f(frequency of the ambulance siren)=821 Hz

v(speed of sound)=345 m/s

Vo(speed of the observer)=0 m/s

To find

f(The ambulance is approaching the person)

Solution

From Doppler effect

f^{i}=(\frac{v+v_{o} }{v-v_{s} })f

As the ambulance approaches the we assign a positive sign for speed "vs" of the ambulance

So

f^{i}=(\frac{v+0}{v-(+v_{s}) } )f\\f^{i}=(\frac{v}{v-v_{s} } )f

Substitute the values from given data

f^{i}=(\frac{345m/s}{345m/s-28.9m/s} )821Hz\\f^{i}=896Hz

5 0
3 years ago
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