Answer:
129,600kg/day
Explanation:
The river is flowing at 30.0
1 = 1000L
Multiply by 1000 to convert to L/s
flowrate of river = 30*1000 =30,000L/s
Convert L/s to litre per day by multiplying by 24*60*60
flowrate of river = 30,000 * 24*60*60 L/day
= 2,592,000,000L/day
if the river contains 50mg of salt in 1L of solution
lets find how many mg of salt (X) is contained in 2,592,000,000L/day
X= 
X= 129,600,000,000 mg/day
convert this value to kg/day by multiply by 
X= 129,600kg/day
Answer:
Remove the glass and have it steel or something to protect it more. And add a filter on top.
Explanation:
Word it different this is my answer
Answer: The first blank is "mechanical energy" The second blank is "chemical energy" and the last blank space would be "potential energy"
So in order of 1st to last blank its "mechanical" "chemical" and "potential"
Answer:
24805.44 J
Explanation:
Step 1:
Data obtained from the question.
Mass (M) = 464g
Initial temperature (T1) = 120°C
Final temperature (T2) = 219°C
Change in temperature (ΔT) = T2 - T1 = 219°C - 120°C = 99°C
Specific heat capacity of lead (C) = 0.129cal/g°C = 4.184 x 0.129 = 0.54J/g°C
Heat (Q) =?
Step 2:
Determination of the heat Q, required the temperature of lead. This is illustrated below
Q = MCΔT
Q = 464 x 0.54 x 99
Q = 24805.44 J
Therefore, 24805.44 J of heat is required to raise the temperature of lead.
Answer:
It depends. what hot spot are you looking for?
