If a synthesis reaction takes place between rubidium and bromine, the chemical formula for the product is _____.
2 answers:
Answer:
c) RbBr.
Explanation:
Hello,
In this case, since rubidium is in group IA, one electron will be eligible to pair during a chemical reaction. In addition, as long as bromine is in group VIIA, when pairing with a metal, just one electron is eligible to pair as well. Now, based on the aforesaid facts, we infer that the undergoing chemical reaction will be:
So the formed product is which is rubidium bromide, that is the c) answer.
Best regards.
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Answer:
(a) 7.11x10⁻⁴ M/s
(b) 2.56 mol.L⁻¹.h⁻¹
Explanation:
(a) The reaction is:
O₃(g) + NO(g) → O₂(g) + NO₂(g) (1)
The reaction rate of equation (1) is given by:
(2)
<u>We have:</u>
k: is the rate constant of reaction = 3.91x10⁶ M⁻¹.s⁻¹
[O₃]₀ = 2.35x10⁻⁶ M
[NO]₀ = 7.74x10⁻⁵ M
Hence, to find the inital reacion rate we will use equation (2):
Therefore, the inital reaction rate is 7.11x10⁻⁴ M/s
(b) The number of moles of NO₂(g) produced per hour per liter of air is:
t = 1 h
V = 1 L
Hence, the number of moles of NO₂(g) produced per hour per liter of air is 2.56 mol.L⁻¹.h⁻¹
I hope it helps you!