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jeyben [28]
3 years ago
10

Question:

Chemistry
1 answer:
den301095 [7]3 years ago
8 0

Answer: I think it’s 4

Explanation:

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1. If temperature is increased, the number of<br> collisions per second
muminat

Answer:

If temperature increases, the number of collisions per second also increase because particles absorb energy.

hope this way the kind of answer you were looking for:)

6 0
3 years ago
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67.029g to three significant figures
alexdok [17]
67.0 Should be th3 answer
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Which step accurately describes how to measure the final burette volume?
8090 [49]
To accurately measure the final volume of a solution in a burette, it is important that you read of the measurement in the lower meniscus like for water and for substances like mercury you read it on the upper meniscus. This is the standard way of reading volumes in laboratory apparatus. Also, it should be that the apparatus standing vertically in a plain surface.
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3 years ago
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What volume of hydrogen will be produced at STP by the reaction of 67.3 g of tin with excess water according to the following re
VikaD [51]

Answer:

Sn + 2H2O ==> Sn(OH)2 + 2H2

67.3 g Sn x 1 mol/119 g x 2 mol H2/mol Sn x 22.4 L/mole = answer in liters

Explanation:

Sn + 2H2O ==> Sn(OH)2 + 2H2

67.3 g Sn x 1 mol/119 g x 2 mol H2/mol Sn x 22.4 L/mole = answer in liters

5 0
3 years ago
What mass of H2 is needed to react with 8.75 g of O2 according to the following equation: O2(g) + H2(g) → H2O(g)?
Alika [10]

Answer:- B: 1.10g H_2 is the right answer.

Solution:- The balanced equation is:

O_2(g)+2H_2(g)\rightarrow 2H_2O(g)

We have been given with 8.75 grams of oxygen and asked to calculate the grams of hydrogen needed to react with given grams of oxygen according to the balanced equation.

From balanced equation, 1 mole of oxygen reacts with 2 moles of hydrogen.

So, let's convert grams of oxygen to moles and multiply it by the mole ratio to calculate the moles of hydrogen that are easily converted to grams on multiplying by it's molar mass.

The complete set up looks as:

8.75g O_2(\frac{1mole}{32g})(\frac{2mole H_2}{1mole O_2})(\frac{2.02g}{1mole})

= 1.10g H_2

Hence, the right option is B: 1.10g H_2 .



7 0
3 years ago
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