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VMariaS [17]
3 years ago
15

What is the Ozone Layer?

Chemistry
1 answer:
kozerog [31]3 years ago
8 0
A layer above the earth that protects the planet from dangerous UV that are sent from the sun
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Calculate the molar mass of K3PO4
julia-pushkina [17]

Answer:

Molar mass of K₃PO₄  = 212.27 g/m

Explanation:

K₃PO₄ (Potassium phosphate)

This is a ionic salt compounded of phosphate and potassium

Mass of potassium = 39.10 g/m

Mass of phosphorus = 30.97 g/m

Mass of oxygen = 16 g/m

Molar mass of K₃PO₄  = 39.10 x3 + 30.97 + 16 x4 = 212.27 g/m

3 0
4 years ago
Why can metals be extracted using carbon
8090 [49]
If a metal is less reactive than carbon, it can be extracted from its oxide by heating with carbon. The carbon displaces the metal from the compound, and removes the oxygen from the oxide. This leaves the metal.
5 0
2 years ago
Consider the following reaction:
PIT_PIT [208]

Answer:

Kc = 3.1x10²

Explanation:

At equilibrium, the velocity of product formation is equal to the velocity of reactants formation. For a generic reaction, the equilibrium constant (Kc) is:

aA + bB ⇄ cC + dD

Kc = \frac{[C]^c*[D]^d}{[A]^a*[B]^b}

Where [X] is the molar concentration of X, and the solid substances are not considered (because it's activity is 1, for the other substances, the activity is substituted for the molar concentration, which forms the equation above).

For the reaction given, let's make an equilibrium chart:

Fe³⁺(aq) + SCN⁻(aq) ⇄ FeSCN²⁺(aq)

1.1*10⁻³       8.2*10⁻⁴           0                  <em> Initial</em>

  -x               -x                  +x                  <em>Reacts</em> (stoichiometry is 1:1:1)

1.1*10⁻³ -x   8.2*10⁻⁴ -x       x                 <em>  Equilibrium</em>

x = 1.8*10⁻⁴ M, so the molar concentrations at equilibrium are:

[Fe⁺³] = 1.1*10⁻³ - 1.8*10⁻⁴ = 9.2*10⁻⁴ M

[SCN⁻] = 8.2*10⁻⁴ - 1.8*10⁻⁴ = 6.4*10⁻⁴ M

[FeSCN⁺²] = 1.8*10⁻⁴ M

Kc = [FeSCN⁺²]/([Fe⁺³]*[SCN⁻])

Kc = (1.8*10⁻⁴)/(9.2*10⁻⁴*6.4*10⁻⁴)

Kc = 306 = 3.1x10²

6 0
3 years ago
Iron(III) oxide is formed when iron combines with oxygen in the air. How many grams of Fe2O3 are formed when 33.4 g of Fe reacts
konstantin123 [22]

    The grams of  Fe₂O₃   that are formed is  47.68 g

<u><em>calculation</em></u>

Step 1: write   the equation for reaction

4 Fe +3O₂ → 2 Fe₂O₃

Step 2: find  the  moles  of Fe

moles = mass÷  molar mass

 = 33.4 g÷55.8 g/mol =0.5986 moles

Step 3 : use the mole ratio to determine the moles of Fe₂O₃

That is  from  equation above Fe:Fe₂O₃  is 4:2 therefore the moles of Fe₂O₃ is  =  0.5986 moles x 2/4 =0.2993 moles

Step 4 : find the mass  of Fe₂O₃

mass = mass x molar mass

The molar mass of Fe₂O₃  = (55.8 x 2 +(15.9 x3) = 159.3 g/mol

mass is therefore =  0.2993 moles x 159.3 g/mol =47.68 g

4 0
3 years ago
Read 2 more answers
NO2 is added to the reaction to speed it up. In which form would this substance be a homogeneous catalyst for this reaction?
sammy [17]

Answer: The correct answer is A

Explanation:

5 0
4 years ago
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