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Verizon [17]
2 years ago
12

How do you find an equation for a line with a slope of 2/3 passing through (1,-4)​

Mathematics
2 answers:
Igoryamba2 years ago
7 0

Answer:

The standard general equation for a straight line is:

y = mx + C. You said the slope of line is 2/3. m is always the slope in this context. So with the numerical value slope we have the line

Y = 2/3 X + C. You also said the line passes through the point (1, -4) that is the X value is 1 and the y value is -4. Substitute these value into the linear equation to find C, as follows

-4 = 2/3 + c. and so C = - 4 - 2/3 = -14/3 and so the equation of line is :

y = 2x/3 + 14/3 or if you like 3y = 2x + 14

It is important to remember that the convention of the bracketted numbers e.g. (1,-4) or ( 1, -4, z), say is that the first number in the brackets indicates the X value, the second the y value and the third, the z value in the case of 3 D coordinates.

mart [117]2 years ago
3 0
*Y=2/3x-6
I believe this is the answer!!! Hope you get a good grade
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At the end of 8 years, Anna paid $400 interest for a loan. If the simple annual interest rate was 4%, how much did Anna borrow?
antiseptic1488 [7]

$1250

Use the formula i = prt

In this case, we don't know P or Principal amount

i = 400

r = .04 *found by diving 4/100*

n = 8

Set formula to solve for P like: P= i/r(n)

P=400/.04(8)

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P = 1250

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Step-by-step explanation:

-(38/21)

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7 0
2 years ago
The figures below are made out of circles, semicircles, quarter circles, and a square. Find the area and the perimeter of each f
WITCHER [35]

Answer:

Part 1) A=36(\pi-2)\ cm^2

Part 2) P=6(\pi+2\sqrt{2})\ cm

Step-by-step explanation:

<u><em>The picture of the question in the attached figure</em></u>

Part 1) Find the area

we know that

The area of the shape is equal to the area of a quarter of circle minus the area of an isosceles right triangle

so

A=\frac{1}{4}\pi r^{2}-\frac{1}{2}(b)(h)

we have that the base and the height of triangle is equal to the radius of the circle

r=12\ cm\\b=12\ cm\\h=12\ cm

substitute

A=\frac{1}{4}\pi (12)^{2}-\frac{1}{2}(12)(12)\\A=(36\pi-72)\ cm^2

simplify

Factor 36

A=36(\pi-2)\ cm^2

Part 2) Find the perimeter

The perimeter of the figure is equal to the circumference of a quarter of circle plus the hypotenuse of the right triangle

The circumference of a quarter of circle is equal to

C=\frac{1}{4}(2\pi r)=\frac{1}{2}\pi r

substitute the given values

C=\frac{1}{2}\pi (12)\\C=6\pi\ cm

Applying the Pythagorean Theorem

The hypotenuse of right triangle is equal to

AC=\sqrt{12^2+12^2}\\AC=\sqrt{288}\ cm

simplify

AC=12\sqrt{2}\ cm

Find the perimeter

P=(6\pi+12\sqrt{2})\ cm

simplify

Factor 6

P=6(\pi+2\sqrt{2})\ cm

4 0
3 years ago
An average of 20 apples were sold from Monday to Friday. After the sales on Saturday and Sunday, the average apples sold per day
avanturin [10]
131 apples were sold on Saturday and Sunday.

Work:
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6 0
2 years ago
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