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Studentka2010 [4]
3 years ago
11

Find the 64th term of the following arithmetic sequence. 17, 26, 35, 44, ...

Mathematics
1 answer:
goblinko [34]3 years ago
8 0

take the difference

26-17=9

35-26=9

the first term is 17

and the nth term is 64

use the formula

tn=a+(n-1) d

let a be 17

let n be 64

let d be 9

then you substitute

t64=17+(64-1)9

=17+(63)9

=17+567

=584

so the 64th term is 584.

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3 years ago
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Answer:

2. n = 11

4. g = -2

6. t = 21

8. n = 4

10. y = -1

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2. 63  = -3(1 - 2n)

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-21=1-2n\\2n=1+21\\2n=22\\n=\frac{22}{2} \\\therefore n=11

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