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xeze [42]
3 years ago
7

How many atoms of potassium and how

Chemistry
1 answer:
Varvara68 [4.7K]3 years ago
8 0
KOH? 6.022 x 10^23 atoms of potassium(K) are in one mole of KOH
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Use the following equation to answer the questions below.
sertanlavr [38]

Answer:

Explanation:

Here is ur answer what you wanna do first is calculate the first and second numbers and letters this should be ur answer = -394 + 2 x (-242) - (-75) + 2 x 0 = -803 kJ/mol

4 0
2 years ago
Suppose the mass of a jelly bean is less than the mass of a gum drop. If you counted out 10 of each kind of candy and measured t
MAVERICK [17]

Answer: Option (a) is the correct answer.

Explanation:

Since it is given that the mass of a jelly bean is less than the mass of a gum drop.

So, when we counted out 10 of each kind of candy and measured the mass of each kind of candy, the mass of the jellybeans would be less than the mass of the gumdrops.

This is because mass of jelly bean is less and even if we take take or more jelly beans then also their total mass will remain less than the total mass of same number of gum drops.

7 0
3 years ago
Read 2 more answers
Calcium chloride contains calcium and chloride ions. Write the ground-state electron configuration for the calcium ion.
Drupady [299]

Answer:

1s2 2s2 2p6 3s2 3p6

Explanation:

Calcium is the 20th element. It has 20 electrons in it's neutral state. The electronic configuration is given as;

1s2 2s2 2p6 3s2 3p6 4s2

However in the compound; calcium chloride, it does not exist in it's neutral state.

CaCl2 --> Ca2+   +   Cl-

In Ca2+ state, it has lost two electrons, The total number of electrons becomes; 20 - 2 = 18 electrons.

The electronic configuration is given as;

1s2 2s2 2p6 3s2 3p6

8 0
2 years ago
Which matter exists in the gaseous state at room temperature?
Tpy6a [65]
Helium i would think so
3 0
3 years ago
Read 2 more answers
How many grams of a 14.0% (w/w) sugar solution contain 62.5<br> of sugar?
Delicious77 [7]

Answer:

m_{solution}=446.4g

Explanation:

Hello,

In this case, by-mass percent is computed in terms of the mass of the solute and the mass of the solvent as shown below:

\% m=\frac{m_{solute}}{m_{solution}} *100\%

Thus, solving for the mass of the solution, we obtain:

\frac{x}{y} m_{solution}=\frac{m_{solute}}{\% m}*100\%\\ \\m_{solution}=\frac{62.5g}{14.0\%}*100\% \\\\m_{solution}=446.4g

Regards.

3 0
3 years ago
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