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3 years ago

7

How many atoms of potassium and how

1 answer:

Varvara68 [4.7K]3 years ago

8 0

KOH? 6.022 x 10^23 atoms of potassium(K) are in one mole of KOH

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Which of the following groups of elements are likely to be radioactive? (5 points) a Actinides b Noble gases c Transition metals

Nataly [62]

Answer:

Actinides

Explanation:

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2 years ago

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3 years ago

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2 years ago

0.030 moles of a weak acid, HA, was dissolved in 2.0 L of water to form a solution. At equilibrium, the concentration of HA was

nikitadnepr [17]

Answer: The value of $k_{a}$ for the weak acid is $3.07 \times 10^{-4}$ .

Explanation:

First, we will calculate the molarity of HA as follows.

[HA] = $\frac{\text{no. of moles}}{\text{volume}}$

= $\frac{0.03 mol}{2 L}$

= 0.015

At equilibrium,

$HA + H_{2}O \rightleftharpoons H_{3}O^{+} + A^{-}$

Initial: 0.015 0 0

Change: -x +x +x

Equilibm: 0.015 - x x x

It is given that, at equilibrium

[HA] = 0.015 - x = 0.013

- x = 0.013 - 0.015

= 0.002

Now, expression for $k_{a}$ of this reaction is as follows.

$k_{a} = \frac{[A^{-}][H_{3}O^{+}]}{[HA]}$

= $\frac{x^{2}}{[HA]}$

= $\frac{(0.002)^{2}}{0.013}$

= $3.07 \times 10^{-4}$

Thus, we can conclude that the value of $k_{a}$ for the weak acid is $3.07 \times 10^{-4}$ .

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2 years ago