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Ray Of Light [21]
2 years ago
15

8) If you apply a force of 50N to an object, but the object doesn't move,

Chemistry
1 answer:
vlada-n [284]2 years ago
7 0

0 J

Work = Force * Displacement

Since displacement is 0 m (object isn't moving), work would also be 0.

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Using the image below, describe in at least 2 paragraphs, what is happening with the arrows. Name and explain the processes and
Eddi Din [679]

Answer: I'm sorry, but we can't see the image from NASA

Explanation:

6 0
3 years ago
The density of water is 1 gm/ml. An object has a mass of 58 grams. What volume must it have in order to float in water?
Keith_Richards [23]

Answer:

58mL

Explanation:

Given parameters:

Density of water  = 1g/mL

Mass of object  = 58g

Unknown:

The volume the object must have to be able to float in water = ?

Solution:

To solve this problem, we know that the object must have density value equal to that of water or less than that of water to be able to float.

We then set its density to that of water;  

   Density  = \frac{mass}{volume}  

      Volume  = \frac{mass}{density}  

So;

      Volume  = \frac{58}{1}   = 58mL

7 0
2 years ago
The reactivity of metals on the periodic table
kari74 [83]

Explanation:

The most reactive metals are found on the left of the periodic table, in the blue column, known as the alkali metals. Their reactivity increases as we go down column (group) one. Reactive metals, when attached to less reactive metals, have the ability to prevent the less reactive metal from rusting.

8 0
3 years ago
What factors affect the speed of a wave? Check all that apply. the amplitude of the wave the energy of the wave the temperature
Lena [83]

Answer:

I believe its 1,2, and 5

Explanation:

4 0
3 years ago
What are the products obtained in the electrolysis of molten nai?
yanalaym [24]
Answer is: sodium (Na) and iodine (I₂).

<span> First ionic bonds in this salt are separeted because of heat: 
</span>NaI(l) → Na⁺(l) + I⁻(l).

Reaction of reduction at cathode(-): Na⁺(l) + e⁻ → Na(l) /×2.

2Na⁺(l) + 2e⁻ → 2Na(l).

Reaction of oxidation at anode(+): 2I⁻(l) → I₂(l) + 2e⁻.

The anode is positive and the cathode is negative.


4 0
3 years ago
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