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bixtya [17]
3 years ago
11

I NEED HELP PLEASE, THANKS! BRAINLIEST :)

Chemistry
1 answer:
adoni [48]3 years ago
8 0

Answer:

Please see the answer in the picture

Explanation:

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The volcano in the image is called Ol Doinyo Lengai. This volcano formed as a result of two plates separating. Which other type
creativ13 [48]

Answer:

Convergent

Explanation:

I did the test

8 0
3 years ago
Read 2 more answers
Which electron transition represents a gain of energy?
xz_007 [3.2K]

The correct answer is (A) from 2nd to 3rd shell.


The explanation :


when a gain of energy is the shift of the electrons from a shell of low energy to the shell of high energy


and we have here 2nd shell is the shell of low energy, and 3rd shell is the shell of high energy.


∴ (A) from 2nd to 3rd shell is the correct answer.

5 0
3 years ago
Cuando viajo, me gusta comprar recuerdos.
kaheart [24]

Answer:

to buy souvenirs

give me big brain

Explanation:

7 0
2 years ago
To what temperature does a 250 ml cylinder containing 0.40 grams of helium gas need to be collected in order for the pressure to
VMariaS [17]

Answer:

T =76.13 K

Explanation:

Given data:

Temperature of gas = ?

Volume of gas = 250 mL(250/1000 = 0.25 L)

Mass of helium = 0.40 g

Pressure of gas = 253.25 kpa (253.25/101 = 2.5 atm)

Solution:

Formula:

PV = nRT

First of all we will determine the number of moles of helium.

Number of moles = mass/ molar mass

Number of moles = 0.40 g/ 4 g/mol

Number of moles = 0.1 mol

Now we will put the values.

R = general gas constant = 0.0821 atm.L/ mol.K

T = PV/nR

T =2.5 atm× 0.25 L /0.1 mol ×0.0821 atm.L/ mol.K

T = 0.625  /0.00821/K

T =76.13 K

6 0
3 years ago
Question 15 How many grams of NaCl are required to make 500.0 mL of a 1.500 M solution? 58.40 g 175.3 g 14.60 g 43.83 g
ExtremeBDS [4]
Hi!

To make 500 mL of a 1,500 M solution of NaCl you'll require 43,83 g

To calculate that, you will need to use a conversion factor to go from the volume of the 1,500 M solution to the required grams. For this conversion factor, you'll use the definition for Molar concentration (M=mol/L) and the molar mass of NaCl. The conversion factor is shown below:

gNaCl=500mLsol* \frac{1L}{1000 mL}* \frac{1,500 mol NaCl}{1Lsol}* \frac{58,4428 g NaCl}{1 mol NaCl} \\ =43,83gNaCl

Have a nice day!
4 0
3 years ago
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