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2.

kap26 [50]

Answer:

A they share two covalent bonds

8 0

3 years ago

Ferrous sulfate (FeSO4) was used in the

BARSIC [14]

Ferrous sulfate (FeSO4) is obtained by the reaction of aqueous ferric sulfate with gaseous sulfur dioxide and water according to the equation below:

Aqueous ferric sulfate = $Fe_2(SO_4)_3_{(aq)}$

Gaseous sulfur dioxide = $SO_2_{(g)}$

Water = $H_2O_{(l)}$

Aqueous sulfuric acid = $H_2SO_4_{ (aq)}$

Aqueous ferrous sulfate = $FeSO_4_{ (aq)}$

Thus, the balance equation becomes:

$Fe_2(SO_4)_3_{(aq)}$ + $SO_2_{(g)}$ + $2H_2O_{(l)}$ $--->$ $2 H_2SO_4_{ (aq)} + 2 FeSO_4_{ (aq)}$

More on ferrous sulfate can be found here: brainly.com/question/10834028

6 0

3 years ago

Write a balanced chemical equation that describes an acid-base reaction that would allow you to determine the moles of aspirin p

Kryger [21]

A balanced equation representing the acid-base reaction that allows the calculation of the moles of aspirin in a sample is

$C_{9} H_{8}O_{4} + NaOH$ ⇒ $C_{9} H_{7}O_{4} Na+ H_{2} O$

Aspirin, also known as acetylsalicylic acid, is a nonsteroidal anti-inflammatory drug used to reduce pain, fever, and/or inflammation, and as an antithrombotic.

Aspirin is a benzoic acid with an ortho-substituted acylated alcohol function (actually a phenol). Therefore, two reactions can occur when aspirin and NaOH are combined: In fact, several aspirin formulations contain this ingredient.

Hence, A balanced equation representing the acid-base reaction that allows the calculation of the moles of aspirin in a sample is

$C_{9} H_{8}O_{4} + NaOH$ ⇒ $C_{9} H_{7}O_{4} Na+ H_{2} O$

To know more about Aspirin, here : brainly.com/question/23878261

#SPJ4

6 0

1 year ago

A student has 70.5 mL of a 0.463 M aqueous solution of sodium bromide. The density of the solution is 1.22 g/mL. Find the follow

AleksandrR [38]

Answer:

a.) 86.01 g.

b.) 3.36 g.

c.) 0.394 m ≅ 0.40 m.

d.) 4.77%.

e.) 3.9%.

Explanation:

a.) mass of the solution:

The density of the solution is the mass per unit volume.

∵ Density of solution = (mass of solution)/(volume of the solution).

∴ Mass of the solution = (density of solution)*(volume of the solution) = (1.22 g/mL)*(70.5 mL) = 86.01 g.

b.) grams of sodium bromide :

Molarity (M) is defined as the no. of moles of solute dissolved per 1.0 L of the solution.

∵ M = (no. of moles of NaBr)/(Volume of the solution (L))

∴ no. of moles of NaBr = M*(Volume of the solution (L)) = (0.463 M )*(0.0705 L) = 0.0326 mol.

∵ no. of moles of NaBr = (mass of NaBr)/(molar mass of NaBr)

∴ mass of NaBr = (no. of moles of NaBr)*(molar mass of NaBr) = (0.0326 mol)*(102.894 g/mol) = 3.36 g.

c.) molality of the solution:

Molality (m) is defined as the no. of moles of solute dissolved per 1.0 kg of the solvent.

∵ m = (no. of moles of NaBr)/(mass of the soluvent (kg))

no. of moles of NaBr = 0.0326 mol,

mass of solvent = mass of the solution - mass of NaBr = 86.01 g - 3.36 g = 82.65 g = 0.08265 kg.

∴ m = (no. of moles of NaBr)/(mass of the soluvent (kg)) = (0.0326 mol)/(0.08265 kg) = 0.394 m ≅ 0.40 m.

d.) % (m/v) of the solution:

∵ (m/v)% = [(mass of solute) /(volume of the solution)]* 100

∴ (m/v)% = [(3.36 g)/(70.5 mL)]* 100 = 4.77%.

e.) % (m/m) of the solution:

∵ (m/m)% = [(mass of solute) /(mass of the solution)]* 100

∴ (m/m)% = [(3.36 g)/(86.01 g)] * 100 = 3.9 %.

4 0

3 years ago

What term expresses the ratio of moles of reactants and products according to the coefficients in the balanced chemical equation

bogdanovich [222]

Answer:

A) mole ratio

Explanation:

A mole ratio, also known as a mole-to-mole ratio, is the ratio between the amounts in moles of one reactant/product to the moles of the other reactant/product. This ratio is determined considering the coefficients in a balanced chemical equation. This ratio is used in chemical problems as a conversion factor between the compounds involved in the reaction.

I hope you find this information useful and interesting! Good luck!

6 0

3 years ago