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Fittoniya [83]
3 years ago
10

In any chemical reaction, the quantities that are preserved are O A. the number of moles and the volumes B. the number of molecu

les and the volumes 0 C. mass and number of atoms D. mass and moles​
Chemistry
1 answer:
Strike441 [17]3 years ago
4 0

Explanation:

Law of conversation of mass applies in any chemical reaction.

The number of moles can be different for each compound being used, as it is based on the different molar masses of each compound.

Hence, the answer is C. mass and number of atoms.

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Answer:

i think its b

Explanation:

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this is why the CO2 is removed and the 02 is released into the atmosphere,   Consumers such as animals, fungi, and bacteria get their energy from this excess biomass either while living or dead and decaying. Oxygen from the atmosphere is combined with carbohydrates to liberate the stored energy. ... Photosynthesis removes CO2 from the atmosphere and replaces it with O2.

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8 0
3 years ago
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What type of solvent would be required to dissolve nonpolar compounds?
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For example, ionic compounds, which are very polar, are often soluble in the polar solvent water. Nonpolar substances are likely to dissolve in nonpolar solvents. For example, nonpolar molecular substances are likely to dissolve in hexane, a common nonpolar solvent.
4 0
1 year ago
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What is the new pressure of 150 mL of a gas that is compressed to 50 mL when the original pressure was 2.0 atm and the temperatu
tatyana61 [14]

Answer:

1) 6.0 atm.

2) 2.066 atm.

Explanation:

  • From the general law of ideal gases:

<em>PV = nRT.</em>

where, P is the pressure of the gas.

V is the volume of the container.

n is the no. of moles of the gas.

R is the general gas constant.

T is the temperature of the gas (K).

<em>1) What is the new pressure of 150 mL of a gas that is compressed to 50 mL when the original pressure was 2.0 atm and the temperature is held constant?</em>

  • At constant T and at two different (P, and V):

<em>P₁V₁ = P₂V₂.</em>

P₁ = 2.0 atm, V₁ = 150.0 mL.

P₂ = ??? atm, V₂ = 50.0 mL.

<em>∴ P₂ = P₁V₁/V₂</em> = (2.0 atm)(150.0 mL)/(50.0 mL) = <em>6.0 atm.</em>

<em>2. A sample of a gas in a rigid container at 30.0°C and 2.00 atm has its temperature increased to 40.0°C. What will be the new pressure?</em>

<em></em>

  • Since the container is rigid, so it has constant V.
  • At constant V and at two different (P, and T):

<em>P₁/T₁ = P₂/T₂.</em>

P₁ = 2.0 atm, T₁ = 30.0°C + 273 = 303 K.

P₂ = ??? atm, T₂ = 40.0°C + 273 = 313 K.

<em>∴ P₂ = P₁T₂/T₁ </em>= (2.0 atm)(313.0 K)/(303.0 K) =<em> 2.066 atm.</em>

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Answer:

The correct answer to the following question will be "Particles".

Explanation:

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