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3 years ago

A triangle has angles that measure 117°, 16°, and 47°. What kind of triangle is it?

Mathematics

2 answers:

Travka [436]3 years ago

7 0

Root 16²+47² = 49.648 ≈ 50
and since 117 > 50
the answer is A.Obtuse

Ket [755]3 years ago

3 0

Obtuse.
117 degrees is greater than 90 degrees. It's obviously obtuse.

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Find the area and the circumference of a circle with radius 4 yd

Romashka [77]

First, let's find the area! The formula to find the area of a circle is πr²

πr²

3.14 · 4²

50.24 yds²

Now let's find the circumference. The formula for this is 2πr

2πr

2 · 3.14 · 4

25.12 yds

Hope this helps!

4 0

2 years ago

If you can answer this, please help !

PolarNik [594]

Answer:

the total of angle's in traingle is 180

so 85+53+c=180

c=180-138

c=42

8 0

2 years ago

Read 2 more answers

Which of the following has a value of 84? <br> A. 512 <br> B. 4,096 <br> C. 32 <br> D. 83

andreev551 [17]

Answer is B. 4,096

I encountered this problem before. This is a trick question.
84 is not really the number 84. It is 8 raised to the 4th power.

So 8⁴ is equal to 4,096.

8 x 8 x 8 x 8 = 4,096

8 x 8 = 64
64 x 8 = 512
512 x 8 = 4,096

6 0

3 years ago

You have a wire that is 20 cm long. You wish to cut it into two pieces. One piece will be bent into the shape of a square. The o

Aleksandr [31]

Answer:

Therefore the circumference of the circle is $=\frac{20\pi}{4+\pi}$

Step-by-step explanation:

Let the side of the square be s

and the radius of the circle be r

The perimeter of the square is = 4s

The circumference of the circle is =2πr

Given that the length of the wire is 20 cm.

According to the problem,

4s + 2πr =20

⇒2s+πr =10

$\Rightarrow s=\frac{10-\pi r}{2}$

The area of the circle is = πr²

The area of the square is = s²

A represent the total area of the square and circle.

A=πr²+s²

Putting the value of s

$A=\pi r^2+ (\frac{10-\pi r}{2})^2$

$\Rightarrow A= \pi r^2+(\frac{10}{2})^2-2.\frac{10}{2}.\frac{\pi r}{2}+ (\frac{\pi r}{2})^2$

$\Rightarrow A=\pi r^2 +25-5 \pi r +\frac{\pi^2r^2}{4}$

$\Rightarrow A=\pi r^2\frac{4+\pi}{4} -5\pi r +25$

For maximum or minimum $\frac{dA}{dr}=0$

Differentiating with respect to r

$\frac{dA}{dr}= \frac{2\pi r(4+\pi)}{4} -5\pi$

Again differentiating with respect to r

$\frac{d^2A}{dr^2}=\frac{2\pi (4+\pi)}{4}$ > 0

For maximum or minimum

$\frac{dA}{dr}=0$

$\Rightarrow \frac{2\pi r(4+\pi)}{4} -5\pi=0$

$\Rightarrow r = \frac{10\pi }{\pi(4+\pi)}$

$\Rightarrow r=\frac{10}{4+\pi}$

$\frac{d^2A}{dr^2}|_{ r=\frac{10}{4+\pi}}=\frac{2\pi (4+\pi)}{4}>0$

Therefore at $r=\frac{10}{4+\pi}$ , A is minimum.

Therefore the circumference of the circle is

$=2 \pi \frac{10}{4+\pi}$

$=\frac{20\pi}{4+\pi}$

4 0

2 years ago

Three times a number increased by 8 is no more than the number decreased by 4.find the number

Inessa05 [86]

3x+ 8= x-4
2x + 8= -4
2x= -12
x= -6

8 0

3 years ago