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Nitella [24]
3 years ago
12

How should the student label each circle in this diagram?

Chemistry
1 answer:
worty [1.4K]3 years ago
8 0

Answer:

Reaction a: chemical, reaction b: nuclear

Explanation:

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Which change will decrease the electric force between two positively charged objects? moving them closer together moving them fa
Nina [5.8K]

Answer:

Moving them farther apart

Explanation:

One can try to change the distance between the two positive charges in such a way that it increases the distance and decreased the electric force.

6 0
3 years ago
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Which is an issue that governments must consider before passing conservation policies?
wariber [46]

Answer:

b. cost to implement conservation policies

Explanation:

4 0
2 years ago
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The pH of lemon juice at 298 K is found to be 2.32. What is the concentration of H3O+ ions in the solution?
Vinvika [58]
PH = -log[H₃O⁺]

[H₃O⁺] = 10^-pH
<span>[H₃O⁺] = 10^-2,32
</span>[H₃O⁺] =0,0047863 ≈<u> 4,79×10×10⁻³ mol/dm³</u>


<em>B) -- 4</em><span><em>,79×10⁻³ M</em></span>
7 0
3 years ago
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One of the pieces of evidence supporting energy quantization was the line spectra of elements. Why does this demonstrate energy
bezimeni [28]

Answer:

c) There are sharp emission lines demonstrating discrete energy levels.

Explanation:

When an element emits energy in the form of radiation, it produces a spectrum of colors on a photographic plate. This spectrum can either be continuous or discrete. In continuous spectrum the spectrum continues without any discrimination between two regions. This represents the continuous emission of radiation, and thus the continuous emission of energy without any break.

On the other hand, the line spectrum consists of discrete and sharp lines, which shows the emission of radiation in a certain amount in a certain time, with a break between emission. Hence, the line spectra supports the quantization of energy.

The correct option is:

<u>c) There are sharp emission lines demonstrating discrete energy levels.</u>

8 0
3 years ago
What is the Kelvin temperature of the air in a tire if the pressure inside the tire is 188 kPa at 32°C. While driving under peri
DENIUS [597]

Answer:

  • <u>414K</u>

Explanation:

The question is not completely clear because some missing parts or grammar (syntax) errors.

Interpreting it, the question is <em>what is the Kelvin temperatue of the air in a tire, when the pressure in the tire has increased to 225 kPa, if the initial conditions of the air inside the tire were 188kPa of pressure and a temperature of 32ºC.</em>

To solve this, you can assume constant volume and use the law of Gay-Lussac for ideal gases:

          \dfrac{P_1}{T_{1}}=\dfrac{P_2}{T_2}

That equation works with absolute temperatures, i.e. Kelvin.

  • 32ºC = 32 + 273.15 K = 305.15K

Then solve for T₂, substitute and compute:

        T_2=P_2\times \dfrac{T_1}{P_{1}}=225kPa\times \dfrac{305.15K}{188kPa}

        T_2=413.90K\approx 414K\longleftarrow answer

8 0
3 years ago
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