Now I'm just going to assume you mean Charles law. So when working with gases, there are 4 properties: pressure, volume, temp, and quantity. The simple gas laws deal with 2, while leaving the other 2 constant. If Charles' Law changes temp and volume, what 2 stay constant? Pressure and quantity
Explanation is in a file
bit.
ly/3a8Nt8n
Answer: The molarity of the malonic acid solution is 0.08335 M
Explanation:
![H_2C_3H_2O_4 +2NaOH\rightarrow Na_2C_3H_2O_4+2H_2O](https://tex.z-dn.net/?f=H_2C_3H_2O_4%20%2B2NaOH%5Crightarrow%20Na_2C_3H_2O_4%2B2H_2O)
To calculate the molarity of acid, we use the equation given by neutralization reaction:
![n_1M_1V_1=n_2M_2V_2](https://tex.z-dn.net/?f=n_1M_1V_1%3Dn_2M_2V_2)
where,
are the n-factor, molarity and volume of acid which is ![H_2C_3H_2O_4](https://tex.z-dn.net/?f=H_2C_3H_2O_4)
are the n-factor, molarity and volume of base which is NaOH.
We are given:
![n_1=2\\M_1=?\\V_1=12.70mL\\n_2=1\\M_2=0.1000M\\V_2=21.17mL](https://tex.z-dn.net/?f=n_1%3D2%5C%5CM_1%3D%3F%5C%5CV_1%3D12.70mL%5C%5Cn_2%3D1%5C%5CM_2%3D0.1000M%5C%5CV_2%3D21.17mL)
Putting values in above equation, we get:
![2\times M_1\times 12.70=1\times 0.1000\times 21.17\\\\M_1=0.08335M](https://tex.z-dn.net/?f=2%5Ctimes%20M_1%5Ctimes%2012.70%3D1%5Ctimes%200.1000%5Ctimes%2021.17%5C%5C%5C%5CM_1%3D0.08335M)
Thus the molarity of the malonic acid solution is 0.08335 M
Answer:
Ya'll should really practice more because things like these are easy
Explanation: