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Sunny_sXe [5.5K]
2 years ago
14

What do you do? Is this correct?

Mathematics
1 answer:
hodyreva [135]2 years ago
3 0

you should put 19 in the tens box and the bottom one is correct

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-3(6 - 3k)<br>I need to Simplify the expression​
sergij07 [2.7K]

Answer:

-18+9k

Step-by-step explanation:

If you use the distributive property, you get:

(-3*6) and (-3*-3k)

If you simplify each of them you get:

-18+9k

8 0
2 years ago
Read 2 more answers
Which are irrational and which are rational ?
a_sh-v [17]

Answer: 8/9 is rational

.2593 irrational

square root of 7: irrational

square root of .25 is rational

square root of 14: irrational

0 is a: rational

square root of 280: irrational

square root of 35: is irrational

.2222: is rational

square root of 3r is a rational number......

Step-by-step explanation:

8 0
3 years ago
Use Stokes' Theorem to evaluate C F · dr F(x, y, z) = xyi + yzj + zxk, C is the boundary of the part of the paraboloid z = 1 − x
Serggg [28]

I assume C has counterclockwise orientation when viewed from above.

By Stokes' theorem,

\displaystyle\int_C\vec F\cdot\mathrm d\vec r=\iint_S(\nabla\times\vec F)\cdot\mathrm d\vec S

so we first compute the curl:

\vec F(x,y,z)=xy\,\vec\imath+yz\,\vec\jmath+xz\,\vec k

\implies\nabla\times\vec F(x,y,z)=-y\,\vec\imath-z\,\vec\jmath-x\,\vec k

Then parameterize S by

\vec r(u,v)=\cos u\sin v\,\vec\imath+\sin u\sin v\,\vec\jmath+\cos^2v\,\vec k

where the z-component is obtained from

1-(\cos u\sin v)^2-(\sin u\sin v)^2=1-\sin^2v=\cos^2v

with 0\le u\le\dfrac\pi2 and 0\le v\le\dfrac\pi2.

Take the normal vector to S to be

\vec r_v\times\vec r_u=2\cos u\cos v\sin^2v\,\vec\imath+\sin u\sin v\sin(2v)\,\vec\jmath+\cos v\sin v\,\vec k

Then the line integral is equal in value to the surface integral,

\displaystyle\iint_S(\nabla\times\vec F)\cdot\mathrm d\vec S

=\displaystyle\int_0^{\pi/2}\int_0^{\pi/2}(-\sin u\sin v\,\vec\imath-\cos^2v\,\vec\jmath-\cos u\sin v\,\vec k)\cdot(\vec r_v\times\vec r_u)\,\mathrm du\,\mathrm dv

=\displaystyle-\int_0^{\pi/2}\int_0^{\pi/2}\cos v\sin^2v(\cos u+2\cos^2v\sin u+\sin(2u)\sin v)\,\mathrm du\,\mathrm dv=\boxed{-\frac{17}{20}}

6 0
3 years ago
Find the value: 3/2 ÷ 5/8 (write your answer as a fraction AND as a decimal number)
Vikki [24]

Answer:

Decimal : 2.4

Fraction: 2 4/10 or 2 2/5

Step-by-step explanation:

hope this helps :) plz mark brainliest to help my rank

4 0
2 years ago
Read 2 more answers
What value of x makes the equation shown true? Show or explain what you did to get your answer. 5x – 1 = 19
Advocard [28]
5x-1=19
1st you add the one over to the 19 and you'll get 20
then you do 5x=20
divide the 5x over to the 20 and your final answer is 4.
5 0
3 years ago
Read 2 more answers
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