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Anvisha [2.4K]
3 years ago
11

A series circuit has a current of 5 A. The circuit contains 10ohms resistor. What is the voltage of the circuit

Physics
1 answer:
d1i1m1o1n [39]3 years ago
3 0

Answer:

50 Volts

Explanation:

Using Ohm's Law

V= I x R

V= 5 x 10

V = 50 V

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The magnetic field lines of a bar magnet spread out from the north end to the south end. South end to the north end. Edges to th
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<h3><u>Answer;</u></h3>

the north end to the south end.

<h3><u>Explanation;</u></h3>
  • Magnetic field lines from a bar magnet form lines that are closed. The direction of magnetic field is taken to be outward from the North pole of the magnet and in to the South pole of the magnet.
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You indicate that a symbol
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B. over the symbol.

Explanation:

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A 1.2 KG rubber ball is being thrown in the air if the ball is traveling at 2.0 M/S when it is 3.0 M off the ground what is the
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37.7 J

Hope this helps! (see pictures)

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3 years ago
During takeoff, an airplane climbs with a speed of 195 m/s at an angle of 15° above the horizontal. The speed and angle constitu
matrenka [14]

Answer:

The horizontal component of the velocity is 188 m/s

The vertical component of the velocity is 50 m/s.

Explanation:

Hi there!

Please, see the figure for a graphic description of the problem. Notice that the x-component of the vector velocity (vx), the y-component (vy) and the vector velocity form a right triangle. Then, we can use trigonometry to obtain the magnitude of vx and vy:

We can find vx using the following trigonometric rule of a right triangle:

cos α = adjacent / hypotenuse

cos 15° = vx / 195 m/s

195 m/s · cos 15° = vx

vx = 188 m/s

The horizontal component of the velocity is 188 m/s

To calculate the y-component we will use the following trigonometric rule:

sin α = opposite / hypotenuse

sin 15° = vy / 195 m/s

195 m/s · sin 15° = vy

vy = 50 m/s

The vertical component of the velocity is 50 m/s.

4 0
3 years ago
A ball is thrown vertically upwards with a velocity of 9.8 m/s. Its velocity after 1 second will be
Reil [10]

\LARGE{ \underline{\underline{ \purple{ \bf{Required \: answer:}}}}}

GiveN:

  • Initial velocity = 9.8 m/s²
  • Accleration due to gravity = -9.8 m/s²
  • Time taken = 1 s

To FinD:

  • Final velocity of the ball?

Step-by-step Explanation:

Using the first Equation of motion,

⇒ v = u + gt

⇒ v = 9.8 + -9.8(1)

⇒ v = 0 m/s

The final velocity is hence <u>0</u><u> </u><u>m</u><u>/</u><u>s</u><u>.</u>

<h3>Note:</h3>

  • While solving questions of under gravity motions using equations of motion, remember the sign convection to avoid mistakes.
  • You can consider positive above the ground and negative for towards it.
5 0
2 years ago
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