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Nikolay [14]
2 years ago
7

What happens to the air resistance on a car as it speeds up? A) decreases b)stays the same C)it changes direction of the car D)i

ncreases
Physics
1 answer:
Naya [18.7K]2 years ago
5 0

the answer is D- increases

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If an object is dropped from a tall building and hits the ground 3.0 s later, how tall is the building?
allsm [11]
D = 1/2 g t^2. It works out to 44.1 meters.
6 0
3 years ago
An equilibrium constant is not changed by a change in pressure <br> a. True<br> b. False
Umnica [9.8K]
Hi There! :)


An equilibrium constant is not changed by a change in pressurea. True
b. False

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7 0
3 years ago
Read 2 more answers
5) Find the initial velocity for a 700 kg car that
Serhud [2]

Answer:

Δv = 12 m/s, but we are not given the direction, so there are really an infinite number of potential solutions.

Maximum initial speed is 40.6 m/s

Minimum initial speed is 16.6 m/s

Explanation:

Assume this is a NET impulse so we can ignore friction.

An impulse results in a change of momentum

The impulse applied was

p = Ft = 1400(6.0) = 8400 N•s

p = mΔv

Δv = 8400 / 700 = 12 m/s

If the impulse was applied in the direction the car was already moving, the initial velocity was

vi = 28.6 - 12 = 16.6 m/s

if the impulse was applied in the direction opposite of the original velocity, the initial velocity was

vi = 28.6 + 12 = 40.6 m/s

Other angles of Net force would result in various initial velocities.

5 0
3 years ago
Use the drop-down menus to identify the parts of DNA. Label A: Label B:
love history [14]

Label A:

Nitrogen bases

Label B:

Sugar-phosphate backbone

7 0
3 years ago
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How many air molecules are in a 13.0×12.0×10.0 ft room (28.2 L=1 ft3)? Assume atmospheric pressure of 1.00 atm, a room temperatu
aksik [14]

Answer:

1963.93 Moles

Explanation:

-We know the standard conversion ratio for the volume of a mole is 1 Mole=22.4L

Given volume of rooms as 13.0ft\times12.0ft\times10ft=1560 ft^3

Convert the volume into liters:1560\times28.2l=43992l

#From our conversion ratio above, we get the volume of air molecules in moles as:

V_m=\frac{43992L}{22.4L}\times 1\ mole\\\\=1963.93\ Moles

Hence, the volume of air molecules is 1963.93 Moles

4 0
2 years ago
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