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Brums [2.3K]
4 years ago
5

Ten points - Check attached image

Mathematics
1 answer:
Rudiy274 years ago
8 0

Answer:

Option D will be the correct option.

Step-by-step explanation:

Formula to get the area of the sector,

Area of the sector = \frac{\theta}{360}(\pi r^{2})

Here θ = Angle subtended by the arc of the sector at the center

r = radius of the circle

Area of the shaded sector = \frac{155}{360}\times \pi (4.3)^2

                                            = 25.01 square inches

Area of the shaded sector will be 25 square inches (approximately).

Option D will be the correct option.

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The region bounded by the given curve is rotated about the specified axis. Find the volume V of the resulting solid by any metho
GalinKa [24]
X^2+(y-2)^2=4 is a circle centered at (0,2) with radius 2.
Thus, when you rotate it around the y-axis (around x=0),
you get a sphere with radius 2.

((which is centered at (x,y,z)=(0,2,0), if you take y to be
the vertical axis ... not that you need to know this for volume))

--------------------------------------------------------------
Volume of a sphere formula: V = (4/3)πr^3.
5 0
3 years ago
Please explain by showing your work.
Levart [38]

Answer:

x=1.8

Step-by-step explanation:

To solve this equation, we can use PEMDAS and the various properties.

First, use the distributive property on all parenthesis, since parenthesis come first.

4x-1+6x+6x+24=52

Now we can use the commutative property to add all like terms.

16x+23=52

Now just subtract on both sides.

52-23=29 so our equation is 16x=29

To isolate x, divide both sides by 16.

x=1.8 rounded up

Hope this helps!

3 0
3 years ago
Suppose that Motorola uses the normal distribution to determine the probability of defects and the number of defects in a partic
Mekhanik [1.2K]

Answer:

\mathbf{P(X < 9.85 \ or \ X> 10.15) \approx 0.3171}     to four decimal places.

\mathbf{P(X < 9.85 \ or \ X> 10.15) =0.0027}  to four decimal places.

Step-by-step explanation:

a)

Assuming X to be the random variable which replace the amount of defectives and follows standard normal distribution whose mean  (μ) is 10 ounces and standard deviation (σ) is 0.15

The values of the random variable differ from mean  by ±  1 \such that the values are either greater than (10+ 0.15) or less than  (10-0.15)

= 10.15 or  9.85.

The  probability that the amount of defectives which are either greater than 10.15 or less than 9.85 can be calculated as follows:

P(X < 9.85 \ or \ X> 10.15) = 1-P ( \dfrac{9.85-10}{0.15}< \dfrac{X-10}{0.15}< \dfrac{10.15-10}{0.15})

P(X < 9.85 \ or \ X> 10.15) = 1- \phi (1) - \phi (-1)

Using the Excel Formula ( = NORMDIST (1) ) to calculate for the value of z =1 and -1 ;we have: 0.841345 and 0.158655 respectively

P(X < 9.85 \ or \ X> 10.15) = 1- (0.841345-0.158655)

P(X < 9.85 \ or \ X> 10.15) =0.31731

\mathbf{P(X < 9.85 \ or \ X> 10.15) \approx 0.3171}     to four decimal places.

b) Through process design improvements, the process standard deviation can be reduced to 0.05.

The  probability that the amount of defectives which are either greater than 10.15 or less than 9.85 can be calculated as follows:

P(X < 9.85 \ or \ X> 10.15) = 1-P ( \dfrac{9.85-10}{0.05}< \dfrac{X-10}{0.05}< \dfrac{10.15-10}{0.05})

P(X < 9.85 \ or \ X> 10.15) = 1- \phi (3) - \phi (-3)

Using the Excel Formula ( = NORMDIST (3) ) to calculate for the value of z =3 and -3 ;we have: 0.99865 and 0.00135 respectively

P(X < 9.85 \ or \ X> 10.15) = 1- (0.99865-0.00135)

\mathbf{P(X < 9.85 \ or \ X> 10.15) =0.0027}  to four decimal places.

(c)  What is the advantage of reducing process variation, thereby causing process control limits to be at a greater number of standard deviations from the mean?

The main advantage of reducing the process variation is that the chance of getting the defecting item will be reduced as we can see from the reduction which takes place from a to b from above.

7 0
4 years ago
What will the coordinate K(3, - 3) be after the translation 8 units to the left and 7 units up.
natita [175]

Answer:

(-5, 4)

Step-by-step explanation:

To find the new coordinate, subtract 8 from the x value and add 7 to the y value:

3 - 8 = -5

-5 will be the new x coordinate

-3 + 7 = 4

4 will be the new y coordinate

So, the coordinate K will be (-5, 4) after the translation

8 0
3 years ago
Read 2 more answers
If k/3 – 9 = 12, what is the value of k?
Ivahew [28]

Answer:

k = 63

Step-by-step explanation:

k/3 - 9 = 12

isolate variable + 9 both sides

k/3 = 21

multiply both sides by three, therefore

k = 63

check:

63/3 - 9 = 12

21 - 9 =12

12 = 12

hope this helps!

7 0
3 years ago
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