3 years ago

PLZ HELP ASAP

1 answer:

sp2606 [1]3 years ago

3 0

Answer:

Explanation:

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The specific heat of water is Cp = 4.184 $\frac{J}{g.^{o}C}$

Explanation:

1. The specific heat can be expressed as:

$Cp=\frac{Q}{m(T_{2}-T_{1})}$

where Q is the energy, m is the mass of water, and T2-T1 express the change in the temperature.

2. Replace values for mass, energy and temperature:

$Cp=\frac{16.736J}{(2.000g)*2.000^{o}C}}$

3. Solve the equation to obtain the specific heat of water:

Cp=4.184 $\frac{J}{g.^{o}C}$

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