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mel-nik [20]
3 years ago
5

A family of organic compounds soluble in organic solvents but not in water is called

Chemistry
1 answer:
Andru [333]3 years ago
5 0
A family of organic compounds soluble in organic solvents but not in water is called<span> __________. The lipid </span>family<span> is made up of triglycerides, phospholipids and ___________. About 95% of the lipids in food and in the human body are ___________. __________ is the best known of the sterols.
 
plz thank me 5 star me </span>
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Is the earths core solid or liquid
melisa1 [442]

Answer:

Liquid

Explanation:

Earth’s core is liquid because it’s hot enough to melt iron, but only in places where the pressure is low enough

5 0
3 years ago
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Pfderghrkldesfnckasjnfckadsjdncvfl.asknd;kjf
ehidna [41]

Answer:

ikr

Explanation:

8 0
4 years ago
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Chlorine can be prepared in the laboratory by the reaction of manganese dioxide with hydrochloric acid, HCl ( aq ) HCl(aq) , as
Daniel [21]

Answer:

1.368 grams of manganese dioxide must b added to HCl to obtain 385 mL of chlorine gas.

Explanation:

Using ideal gas equation:

PV = nRT

where,

P = Pressure of chlorine gas = 765 Torr=\frac{765}{760}atm

1 atm = 760 Torr

V = Volume of chlorine gas = 385 mL = 0.385 L ( 1 mL - 0.001 L)

n = number of moles of chlorine gas = ?

R = Gas constant = 0.0821 L.atm/mol.K

T = Temperature of chlorine gas =25 °C= 25 + 273 K =  300 K

Putting values in above equation, we get:

(\frac{765 }{760}atm)\times 0.385 L=n\times (0.0821L.atm/mol.K)\times 300K\\\\n=0.01573 mole

MnO_2(s)+4HCl(aq)\rightarrow MnCl_2(aq)+2H_2O(l)+Cl_2(g)

According to reaction, 1 mole of chlorine gas is obtained from 1 mole of manganese dioxide ,then 0.01573 moles of chlorine gas will be obtained from :

\frac{1}{1}\times 0.01573 mol=0.01573 mol of manganese dioxide

Mass of 0.01573 moles of manganese dioxide:

0.01573 mol × 86.94 g/mol = 1.368 g

1.368 grams of manganese dioxide must b added to HCl to obtain 385 mL of chlorine gas.

5 0
4 years ago
Enter your answer in the provided box. Find the pH of a buffer that consists of 0.34 M HBrO and 0.89 M KBrO (PK, of HBrO = 8.64)
11111nata11111 [884]

Answer : The  pH of buffer is 9.06.

Explanation : Given,

pK_a=8.64

Concentration of HBrO = 0.34 M

Concentration of KBrO = 0.89 M

Now we have to calculate the pH of buffer.

Using Henderson Hesselbach equation :

pH=pK_a+\log \frac{[Salt]}{[Acid]}

pH=pK_a+\log \frac{[KBrO]}{[HBrO]}

Now put all the given values in this expression, we get:

pH=8.64+\log (\frac{0.89}{0.34})

pH=9.06

Therefore, the pH of buffer is 9.06.

6 0
4 years ago
How many grams of sodium Phosphate is needed to prepare 5.0 L of a 2.6M solution ?
Diano4ka-milaya [45]

Molarity is the ratio of the moles and the volume. The mass of 2.6 M sodium phosphate solution is 2131.22 gms.

<h3>What is mass?</h3>

Mass is the product of the moles and the molar mass of the substance. It is given as,

Mass = Moles × Molar mass

The moles from molar concentration is used to calculate mass as:

Mass = Molarity × volume × molar mass

= 2.6 × 5.0 × 163.94

= 2131.22 gms

Therefore, 2131.22 gms is the mass of sodium phosphate.

Learn more about mass here:

brainly.com/question/9829994

#SPJ1

6 0
2 years ago
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