Question

Calculate the specific heat of water if 16.736 J of energy are required to heat 2.000

Answer 1

Answer:

The specific heat of water is Cp = 4.184 $\frac{J}{g.^{o}C}$

Explanation:

1. The specific heat can be expressed as:

$Cp=\frac{Q}{m(T_{2}-T_{1})}$

where Q is the energy, m is the mass of water, and T2-T1 express the change in the temperature.

2. Replace values for mass, energy and temperature:

$Cp=\frac{16.736J}{(2.000g)*2.000^{o}C}}$

3. Solve the equation to obtain the specific heat of water:

Cp=4.184$\frac{J}{g.^{o}C}$