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Bogdan [553]
3 years ago
10

Consider the reaction 2 CO + O2 → 2 CO2 .What is the percent yield of carbon dioxide

Chemistry
1 answer:
Wewaii [24]3 years ago
7 0

Answer:

Y=50.9\%

Explanation:

Hello,

In this case, given the reaction, we can directly compute the theoretically yielded grams of carbon dioxide, considering the 2:2 molar ratio between carbon monoxide (molar mass = 28 g/mol) and carbon dioxide (molar mass = 44 g/mol) and the initial reacting grams of carbon monoxide in excess oxygen:

m_{CO_2}^{theoretical}=10gCO*\frac{1molCO}{28gCO}*\frac{2molCO_2}{2molCO}*\frac{44gCO_2}{1molCO_2}   =15.7gCO_2

Thus, as only 8 g were actually yielded, we compute the percent yield:

Y=\frac{8g}{15.7g}*100\% \\\\Y=50.9\%

Best regards.

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A certain first-order reaction 45% complete in 65seconds, determine the rate constant and the half life for the process ​
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The rate constant : k = 9.2 x 10⁻³ s⁻¹

The half life : t1/2 = 75.3 s

<h3>Further explanation</h3>

Given

Reaction 45% complete in 65 s

Required

The rate constant and the half life

Solution

For first order ln[A]=−kt+ln[A]o

45% complete, 55% remains

A = 0.55

Ao = 1

Input the value :

ln A = -kt + ln Ao

ln 0.55 = -k.65 + ln 1

-0.598=-k.65

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The half life :

t1/2 = (ln 2) / k

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From each drop-down menu, a solid has (a definite volume and a definite shape), a Liquid has (a definite volume) and gas has ( non of the above)

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Answer:

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The reaction of lithium hydroxide (LiOH) with chlorous acid (HClO₂) is:

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<em>That means, 1 mole of hydroxide reacts per mole of acid</em>

Moles of  20.0 mL = 0.0200L of 0.345M chlorous acid are:

0.0200L ₓ (0.345mol / L) = <em>6.90x10⁻³ moles of HClO₂</em>

To neutralize this acid, you need to add the same number of moles of LiOH, that is 6.90x10⁻³ moles. As the LiOH contains 0.250 moles / L:

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