Question

Consider the reaction 2 CO + O2 → 2 CO2 .What is the percent yield of carbon dioxide

Answer 1

Answer:

$Y=50.9\%$

Explanation:

Hello,

In this case, given the reaction, we can directly compute the theoretically yielded grams of carbon dioxide, considering the 2:2 molar ratio between carbon monoxide (molar mass = 28 g/mol) and carbon dioxide (molar mass = 44 g/mol) and the initial reacting grams of carbon monoxide in excess oxygen:

$m_{CO_2}^{theoretical}=10gCO*\frac{1molCO}{28gCO}*\frac{2molCO_2}{2molCO}*\frac{44gCO_2}{1molCO_2} =15.7gCO_2$

Thus, as only 8 g were actually yielded, we compute the percent yield:

$Y=\frac{8g}{15.7g}*100\% \\\\Y=50.9\%$

Best regards.