I'm thinking a hypothesis theory, form a guess and proceed to experiment your hypothesis, leading to a definate theory....
Answer:
The ΔG° is 29 kJ and the reaction is favored towards reactant.
Explanation:
Based on the given information, the ΔH°rxn or enthalpy change is 41.2 kJ, the ΔS°rxn or change in entropy is 42.1 J/K or 42.1 * 10⁻³ kJ/K. The temperature given is 289 K. Now the Gibbs Free energy change can be calculated by using the formula,
ΔG° = ΔH°rxn - TΔS°rxn
= 41.2 kJ - 289 K × 42.1 × 10⁻³ kJ/K
= 41.2 kJ - 12.2 kJ
= 29 kJ
As ΔG° of the reaction is positive, therefore, the reaction is favored towards reactant.
Answer:
Explanation:
We are asked to find the volume of a substance.
We are given the density and the mass. The density of a substance is its mass per unit volume. The formula for calculating density is:
We know the density of the substance is 13.6 grams per cubic centimeter and the mass is 3.0 grams.
Substitute these values into the formula.
We are solving for the volume, so we must isolate the variable v. First, cross multiply. Multiply the first numerator by the second denominator, then multiply the first denominator by the second numerator.
Multiply on the right side of the equation.
The variable is being multiplied by 13.6 grams per cubic centimeters. The inverse operation of multiplication is division, so we divide both sides of the equation by 13.6 g/cm².
The units of grams cancel.
The original measurement of density has 3 significant figures and the measurement of mass has 2. Our answer must have the least number of sig figs, which is 2. For the number we found, that is the hundredth place. The 0 in the thousandth place tells us to leave the 2 in the hundredth place.
The volume of the substance is approximately <u>0.22 cubic centimeters.</u>
Answer:
The volume of 2M stock solution added = 2 mL
The volume of water = 198 mL
Explanation:
Considering
Given that:
So,
<u>The volume of 2M stock solution added = 2 mL</u>
<u>The volume of water = 200 - 2 mL = 198 mL</u>
Answer:
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to solve this problem by using the combined gas law:
Thus, we solve for the final volume by solving for V2 as follows:
Now, we plug in the variables to obtain the result in milliliters and making sure we have both temperatures in Kelvins:
Regards!