We want:
S(s) + O2(g) --> SO2(g)
So the following are the given:
1) S(s) + 3/2O2(g) --> SO3(g) ∆H = -395.8 kJ/mole
2) 2SO2 + O2 --> 2SO3(g) ∆H = -198.2 kJ/mole
Reverse Equation 2) and then divide by 2
SO3(g) --> SO2(s) + 1/2O2(g) ∆H = +99.1 kJ/mole
Add Equation 1)
S(s) + O2(g) --> SO2(g) ∆H = -296.7 kJ/mole
The low temperature outside lowers the volume of the gas according to Charles' law because this law describes how a gas will behave at constant pressure. It shows that the volume of a given mass of a gas is directly proportional to the absolute temperature provided the pressure remains constant. An increase in temperature leads to an increase in volume while a decrease reduces the volume. This is due to the reduction in the distances traveled by the vibrating particles of the gas because of the lost kinetic energy.
Explanation:
To balance this chemical equation-
see
Balanced form:-
CaO + 2 HCl ==. CaCl2 + H2O
.
Answer:
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I hope this answers you. If not, I may change something accordingly.
Explanation:
Let the volume of the solution be 100 ml.
As the volume of glycol = 50 = volume of water
Hence, the number of moles of glycol = 
= 
= 
= 0.894 mol
Hence, number of moles of water = 
= 2.77
As glycol is dissolved in water.
So, the molality = 
= 17.9
Therefore, the expected freezing point = 
= 
Thus, we can conclude that the expected freezing point is .
